Question

具有这样的表格：

name  ZK04_COUNT  ZK05_COUNT  ZK04_PRICE  ZK05_PRICE
A     15           0             150.00      0 
A     0            20              0         223.00
B     11           0             75.00       0
B     0            24              0         250.00

我正在尝试将其转为类似这样的内容：

name  ZK04_COUNT  ZK05_COUNT  ZK04_PRICE  ZK05_PRICE
A         15          20        150.00       223.00
B         11          24         75.00       250.00

我的代码如下：

SELECT *
FROM (
      SELECT 
       r.name
      ,r.AUART
      , CASE WHEN r.AUART = 'ZK05' THEN count(r.MATNR) ELSE '' END AS ZK05_COUNT
      , CASE WHEN r.AUART = 'ZK04' THEN count(r.MATNR) ELSE '' END AS ZK04_COUNT
      , CONVERT(money, sum(CAST(netpr as MONEY)), 1) as ToplamTutar  
      FROM GARANTI_YP_RAPORU as r
      group by r.name ,r.AUART
     ) as gTablo
PIVOT
(
  SUM(ToplamTutar)

  FOR gTablo.AUART IN ([ZK05],[ZK04])
)
AS p1

我希望输出在单行中。怎么办？

Answer 1

这真的不需要PIVOT。
仅按名称将它们分组，然后使用条件聚合即可。

SELECT r.name
, COUNT(CASE WHEN r.AUART = 'ZK04' THEN r.MATNR END) AS ZK04_COUNT
, COUNT(CASE WHEN r.AUART = 'ZK05' THEN r.MATNR END) AS ZK05_COUNT
, CAST(SUM(CASE WHEN r.AUART = 'ZK04' THEN r.netpr ELSE 0 END) AS MONEY) AS ZK04_PRICE
, CAST(SUM(CASE WHEN r.AUART = 'ZK05' THEN r.netpr ELSE 0 END) AS MONEY) AS ZK05_PRICE
FROM GARANTI_YP_RAPORU as r
GROUP BY r.name
ORDER BY r.name

如何使用数据透视表进行分组

1 个答案: