我的JSON如下:
{
"id": "id1",
"results": [
{
"exceed_size": "yes",
"rows_count": 1001,
"runtime_seconds": 0.02199999988079071,
"columns": [
"COL_1",
"COL_2",
"COL_3",
"COL_4",
"COL_5",
"COL_6",
"COL_7",
"COL_8",
"COL_9"
],
"columns_type": [
"number",
"string",
"string",
"string",
"number",
"time",
"time",
"number",
"string"
],
"limit": 1000,
"index": 0,
"rows": [
[
"9",
" C68894",
" ",
"",
"0",
"2018-05-02 03:13:00.0",
"2017-12-02 22:32:00.0",
"",
"Approved "
],
[
"65",
"325806 ",
"msm ",
" ",
"2",
"2018-05-02 03:13:00.0",
"2018-07-06 06:00:00.0",
"13",
"Approved "
],
...
]
},
...
]
}
我正在使用Play Framework提供的JSON库进行JSON解析。
如果您查看rows
值,则它是JsArray
字符串值中的JsArray
。我一直在尝试将rows
转换为案例类的对象列表,其中我的案例类如下:
case class Rows(col_1: String, col_2: String, ... , col_9: String)
我曾尝试做类似的事情:
val rows = (response \\ "rows").head.as[List[List[(String, String, ... , String)]]].flatten
尝试这种方式引发了一个错误,我确信这是行不通的。如何将这样的JsArray
转换为案例类的对象列表?
编辑1:
按照@MilanRegmi的建议,我尝试了:
implicit val jsonFormat: Format[Rows] = Json.format[Rows]
val emails = (response \ "results" \ "rows").as[JsArray]
.value.map(j => j.validate[Rows].get)
尝试此操作会导致:
Exception in thread "main" play.api.libs.json.JsResultException: JsResultException(errors:List((,List(JsonValidationError(List([{"exceed_size":"yes","rows_count":1001,"runtime_seconds":0.01600000075995922,"columns":["COL_1","COL_2","COL_3","COL_4","COL_5","COL_6","COL_7","COL_8","COL_9"],"columns_type":["number","string","string","string","number","time","time","number","string"],"limit":1000,"index":0,"rows":[["9"," C68894","","","0","2018-05-02 03:13:00.0","2017-12-02 22:32:00.0","","Approved "],["65","325806 ","msm "," ","2","2018-05-02 03:13:00.0","2018-07-06 06:00:00.0","13","Approved "],...]}] is not an object),WrappedArray())))))
at play.api.libs.json.JsReadable$$anonfun$2.apply(JsReadable.scala:25)
at play.api.libs.json.JsReadable$$anonfun$2.apply(JsReadable.scala:25)
at play.api.libs.json.JsError.fold(JsResult.scala:64)
at play.api.libs.json.JsReadable$class.as(JsReadable.scala:23)
at play.api.libs.json.JsUndefined.as(JsLookup.scala:181)
at com.cmdwldap.restapi.User.getEntitlementUserData(User.scala:150)
at com.cmdwldap.restapi.User$.main(User.scala:168)
at com.cmdwldap.restapi.User.main(User.scala)
PS:第150行对应于提到val emails
的地方。
答案 0 :(得分:1)
尝试一下:
val rows: Seq[Rows] = (json \ "result" \ "rows").as[JsArray].value.map(j => j.validate[Rows].get)
更新:
多次询问您的问题后。我现在收到你的问题了。您要将List[List[String]
转换为CaseClass
。
首先,您不能直接将字符串列表数组转换为案例类。因此,您需要将Array[String]
转换为JsObject
,其中key
应该是该类的fieldName
。之后,我们可以使用反射来获取fieldName
。然后,我们需要使用JsObject
创建caseClass
来匹配List[String]
和fieldName
。
从语法上来说,上述情况可以通过以下方式解决:
case class Rows(col1: Option[String] = None,
col2: Option[String] = None,
col3: Option[String] = None,
col4: Option[String] = None,
col5: Option[String] = None,
col6: Option[String] = None,
col7: Option[String] = None,
col8: Option[String] = None,
col9: Option[String] = None)
implicit val reads = Json.reads[Rows]
这是我们的案例类和隐式reads
。现在,上面解释的部分如下:
import scala.reflect.runtime.universe._
def classAccessors[T: TypeTag]: List[MethodSymbol] = typeOf[T].members.collect {
case m: MethodSymbol if m.isCaseAccessor => m
}.toList
val rowFieldNames = classAccessors[Rows].map(k => k.name.toString)
val results = (json \ "results").as[JsArray].value.flatMap{
r => (r \ "rows").as[JsArray].value
}.map{row =>
val rowArray = row.as[JsArray]
val rowArraySeq = rowArray.value.map(_.as[JsString]).map(_.value)
val map = rowArraySeq.foldLeft(Map.empty[String, JsValue]){
(r, c) =>
val indexOfCurrentValue = rowArraySeq.indexOf(c)
val fieldName = rowFieldNames(indexOfCurrentValue)
r.+((fieldName, JsString(c)))
}
val rowJsObject = JsObject(map)
Json.toJson(rowJsObject)
}.toList