Question

我有从api返回的数据，像这样

var data =   {
        "entities": [
            {

                "documentbody": Base64String,
                "filename": "http-status-code-cheat-sheet1.png",
                "filesize": 204326,
               "mimetype": "image/png",

            },
             {

                "documentbody": null,
                "filename": "http-status-code-cheat-sheet2221.png",
                "filesize": 204326,
                "mimetype": "image/png",
            }
        ]
    }

我想创建一个看起来像这样的新数组

var images = [ 
{  imgsrc:(documentBodyValue),imgDesc:(fileNameValue)},
{imgsrc:(documentBodyValue),imgDesc:(fileNameValue)}
]

我尝试使用地图功能let result = data.entities.map(a => a.filename); 但这只会将值返回到新数组中。如何创建一个具有不同键但原始数组中的值不同的新数组？

Answer 1

只需从地图中为每个项目返回一个新对象即可。

let result = data.entities.map(a => ({imgsrc: a.documentbody, imgDesc: a.filename}));

Answer 2

您的尝试几乎是正确的。您可以使用{key: value, ...}语法映射到obj而不是值。例如：

var data = {
  "entities": [
    {

      "documentbody": 'Base64String',
      "filename": "http-status-code-cheat-sheet1.png",
      "filesize": 204326,
      "mimetype": "image/png",

    },
    {

      "documentbody": null,
      "filename": "http-status-code-cheat-sheet2221.png",
      "filesize": 204326,
      "mimetype": "image/png",
    }
  ]
};

let result = data.entities.map(a => ({imgsrc: a.documentbody, imgDesc: a.filename}));
console.log(result);

Answer 3

var images = []
data.entities.forEach(entry => {
    images.push({imgsrc: entry.documentbody, imgDesc: entry.filename})
})

将值和键从一个数组复制到另一个

3 个答案: