Question

我正在编写纸牌游戏。如何通过父类将已经创建的卡片分配给对象？

我试图用这样的方法创建一个新对象：

name = Card(suit1, face1, value1)

但是由于我在此之前声明了名称，因此它无法正常工作。如果在定义变量name之后打印名称，则输出为：7Hearts, 7Diamonds, 7Clubs, 7Spades, 8Hearts, 8Diamonds... 我想在Card类中创建对象，以便为 print(7Hearts.suit, 7Hearts.face, 7Hearts.value) 是

>>> (Hearts, 7, 7)

或 print(AceSpades.suit, AceSpades.face, AceSpades.value)

>>> (Spades, Ace, 11)

from random import *
class Card(object):
    def __init__(self, suit, face, value):
        self.suit = suit
        self.face = face
        self.value = value


class Deck(Card):
    def __init__(self):

        suits = ['Hearts', 'Diamonds', 'Clubs', 'Spades']
        ranks = range(7, 15)
        for rank1 in ranks:
            for suit1 in suits:
                if rank1 == 11:
                    face1 = 'Jack'
                    value1 = 2
                elif rank1 == 12:
                    face1 = 'Queen'
                    value1 = 3
                elif rank1 == 13:
                    face1 = 'King'
                    value1 = 4
                elif rank1 == 14:
                    face1 = 'Ace'
                    value1 = 11
                else:
                    face1 = str(rank1)
                    value1 = rank1

                name = "{0}{1}".format(face1, suit1)

Answer 1

您既不需要也不想继承。 Deck只是卡的集合。

class Deck(object):
    def __init__(self):
        self.cards = []
        suits = ['Hearts', 'Diamonds', 'Clubs', 'Spades'],
        ranks = {11: 'Jack', 12: 'Queen', 13: 'King', 14: 'Ace'}
        values = {11: 2, 12: 3, 13: 4, 14: 11}
        for suit in suits:
            for rank in range(7,15):
                card_rank = ranks.get(rank, str(rank))
                value = values.get(value, value)
                self.cards.append(Card(suit, card_rank, value))

您可能会使用继承来代表不同种类的套牌：扑克套牌，pinochle套牌等。Deck本身具有用于改组的方法，但是每个子类都会构造{ {1}}个适合该卡组的对象。

在父类中创建对象

1 个答案: