Question

如果列类型为DateTime，我如何按小时将LINQ to SQL查询的结果分组？

Answer 1

这是技术时间的解决方案（无背景）。

var query = myDC.Orders
    .GroupBy(x => x.OrderDate.Hour)
    .Select(g => new {
        Hour = g.Key,
        Amount = g.Sum(x => x.OrderAmount)
    });

产生这个：

SELECT SUM([t1].[OrderAmount]) AS [Amount], [t1].[value] AS [Hour]
FROM (
    SELECT DATEPART(Hour, [t0].[OrderDate]) AS [value], [t0].[OrderAmount]
    FROM [dbo].[Orders] AS [t0]
    ) AS [t1]
GROUP BY [t1].[value]

这是营业时间的解决方案（context-ful）。

DateTime zeroDate = new DateTime(2008, 1, 1);

var query = myDC.Orders
    .GroupBy(x => System.Data.Linq.SqlClient.SqlMethods.DateDiffHour(zeroDate, x.OrderDate)
    )
    .Select(g => new { Hours = g.Key, Amount = g.Sum(x => x.OrderAmount) })
    .Select(x => new { Hour = zeroDate.AddHours(x.Hours), Amount = x.Amount});

产生这个：

SELECT DATEADD(ms, (CONVERT(BigInt,(CONVERT(Float,[t2].[value2])) * 3600000)) % 86400000, DATEADD(day, (CONVERT(BigInt,(CONVERT(Float,[t2].[value2])) * 3600000)) / 86400000, @p1)) AS [Hour], [t2].[value] AS [Amount]
FROM (
    SELECT SUM([t1].[OrderAmount]) AS [value], [t1].[value] AS [value2]
    FROM (
        SELECT DATEDIFF(Hour, @p0, [t0].[OrderDate]) AS [value], [t0].[OrderAmount]
        FROM [dbo].[Orders] AS [t0]
        ) AS [t1]
    GROUP BY [t1].[value]
    ) AS [t2]

呃 - bigint / float /毫秒的东西很丑陋，很难验证。我更喜欢在客户端进行添加：

var results = myDC.Orders
    .GroupBy(x => System.Data.Linq.SqlClient.SqlMethods.DateDiffHour(zeroDate, x.OrderDate)
    )
    .Select(g => new { Hours = g.Key, Amount = g.Sum(x => x.OrderAmount) })
    .ToList()
    .Select(x => new { Hour = zeroDate.AddHours(x.Hours), Amount = x.Amount});

产生这个：

SELECT SUM([t1].[OrderAmount]) AS [Amount], [t1].[value] AS [Hours]
FROM (
    SELECT DATEDIFF(Hour, @p0, [t0].[OrderDate]) AS [value], [t0].[OrderAmount]
    FROM [dbo].[Orders] AS [t0]
    ) AS [t1]
GROUP BY [t1].[value]

这是进行上下文时间的第三种方式。这个非常友好，但数据库中存在字符串逻辑（yuck）。

var query = myDC.Orders
    .GroupBy(x => new DateTime(x.OrderDate.Year, x.OrderDate.Month, x.OrderDate.Day, x.OrderDate.Hour, 0, 0))
    .Select(g => new { Hour = g.Key, Amount = g.Sum(x => x.OrderAmount) });

生成

SELECT SUM([t1].[OrderAmount]) AS [Amount], [t1].[value] AS [Hour]
FROM (
    SELECT CONVERT(DATETIME, (CONVERT(NCHAR(4), DATEPART(Year, [t0].[OrderDate])) + ('-' + (CONVERT(NCHAR(2), DATEPART(Month, [t0].[OrderDate])) + ('-' + CONVERT(NCHAR(2), DATEPART(Day, [t0].[OrderDate])))))) + (' ' + (CONVERT(NCHAR(2), DATEPART(Hour, [t0].[OrderDate])) + (':' + (CONVERT(NCHAR(2), @p0) + (':' + CONVERT(NCHAR(2), @p1)))))), 120) AS [value], [t0].[OrderAmount]
    FROM [dbo].[Orders] AS [t0]
    ) AS [t1]
GROUP BY [t1].[value]

LINQ to SQL - 按小时分组

1 个答案: