Question

我无法从API得到任何响应。我正在使用翻新库进行联网。这是我的代码

LoginApi loginApi = APIClient.getApiClient().create(LoginApi.class);
    Call<Login> call = loginApi.loginApiCall("jkchoudhary121@gmail.com", "123456");
    call.enqueue(new Callback<Login>() {
        @Override
        public void onResponse(@NonNull Call<Login> call, @NonNull Response<Login> response) {

            if (response.isSuccessful()){
                Log.i("Response", response.toString());
            }
            else {
                Log.i("Error", "Wrong");
            }
        }

        @Override
        public void onFailure(Call<Login> call, Throwable t) {
            Log.i("Error", t.getMessage());
        }
    });

我尝试用两种方式定义改造实例，但仍然没有得到响应。

这是我的Web服务。

public class APIClient {


private static final String base_url = "https://myUrl/api/v1/users/";

private static Retrofit retrofit = null;
// private static Gson gson = new GsonBuilder().setLenient().create();

private static OkHttpClient okHttpClient = new OkHttpClient.Builder()
        .connectTimeout(7, TimeUnit.MINUTES)
        .readTimeout(7, TimeUnit.MINUTES)
        .writeTimeout(7, TimeUnit.MINUTES)
        .build();

//
public static Retrofit getApiClient() {
    if (retrofit == null) {
        //scalar is for text and gson for json obect and arrays
        retrofit = new Retrofit.Builder().baseUrl(base_url)
                .client(okHttpClient)
                .addConverterFactory(GsonConverterFactory.create())
                .build();
    }
    return retrofit;
}

}

该呼叫进入onReponse，但未返回任何内容。这是我的Login APi界面。

public interface LoginApi {

//login
@FormUrlEncoded
@POST("login")
Call<Login> loginApiCall(@Field("email") String email,
                         @Field("password") String password);

//signup
@FormUrlEncoded
@POST("register")
Call<JSONObject> signupApiCall(@Field("email") String email,
                             @Field("password") String password);

}

这是我的Pojo课程。

public class Login {


@SerializedName("error")
private boolean error;

@SerializedName("message")
private String message;

public Login(boolean error, String message) {
    this.error = error;
    this.message = message;
}

public boolean getError() {
    return error;
}

public void setError(boolean error) {
    this.error = error;
}

public String getMessage() {
    return message;
}

public void setMessage(String message) {
    this.message = message;
}

}

我的json响应看起来像这样

"error": "False",
    "message": "Logged in successfully",

Answer 1

您的代码看起来不错。尝试增加超时值。更改您的代码：

private static OkHttpClient okHttpClient = new OkHttpClient.Builder()
    .connectTimeout(60, TimeUnit.MINUTES)
    .readTimeout(100, TimeUnit.MINUTES)
    .writeTimeout(100, TimeUnit.MINUTES)
    .build();``

`

无法获得API的回复

1 个答案: