根据键值对将对象组合到数组中

Question

我有一个带有对象的动态数组，但似乎无法弄清楚如何在只需要更改某些数据的地方合并/删除对象。

我尝试在两个for循环中遍历代码，但是在保留其他数据的同时无法合并它们。

var record = [
  {
    client: "Client One",
    client_project: "Internal",
    project_task: "Other",
    project_task_id : '1234a',
    day_of_week: "Monday",
    hours: "8",
    weekDay:{
      'Monday':'8',
      'Tuesday':'0',
      'Wednesday':'0',
      'Thursday':'0',
      'Friday':'0',
      'Saturday':'0',
      'Sunday':'0'
    }
  },
  {
    client: "Client Two",
    client_project: "Client Two Staff Aug #12",
    project_task: "Development",
    project_task_id : '7284b',
    day_of_week: "Tuesday",
    hours: "3",
    weekDay:{
      'Monday':'0',
      'Tuesday':'3',
      'Wednesday':'0',
      'Thursday':'0',
      'Friday':'0',
      'Saturday':'0',
      'Sunday':'0'
    }
  },
  {
    client: "Client One",
    client_project: "Internal",
    project_task: "Other",
    project_task_id : '1234a',
    day_of_week: "Tuesday",
    hours: "5",
    weekDay:{
      'Monday':'0',
      'Tuesday':'5',
      'Wednesday':'0',
      'Thursday':'0',
      'Friday':'0',
      'Saturday':'0',
      'Sunday':'0'
    }
  }
]

预期输出如下所示

  {
    client: "Client One",
    client_project: "Internal",
    project_task: "Other",
    project_task_id : '1234a',
    day_of_week: ["Monday", "Tuesday"],
    hours: ["8","5"],
    weekDay:{
      'Monday':'8',
      'Tuesday':'5',
      'Wednesday':'0',
      'Thursday':'0',
      'Friday':'0',
      'Saturday':'0',
      'Sunday':'0'
    }
  },
  {
    client: "Client Two",
    client_project: "Client Two Staff Aug #12",
    project_task: "Development",
    project_task_id : '7284b',
    day_of_week: "Tuesday",
    hours: "3",
    weekDay:{
      'Monday':'0',
      'Tuesday':'3',
      'Wednesday':'0',
      'Thursday':'0',
      'Friday':'0',
      'Saturday':'0',
      'Sunday':'0'
    }
  }
]

我认为也许我坚持的是如何遍历所有对象，然后每次都遍历所有对象以构建正确的对象数组。

我一直在玩的是

var newArray = [];

for(var item in record){
  if(record[item].project_task_id == record[item++].project_task_id ){
    //combine weekDays and remove unnecessary objects
  }
}

OR

for(var item in record){
 for(var nextItem in record){
    if(record[item].project_task_id == record[nextItem].project_task_id ){
      //combine weekDays and remove unnecessary objects
   }
  }
}