昨晚,我正在编写我的第一个pySFTP笔记本,并且能够使它正常工作。我上床睡觉一直在工作,但现在没有了。我在连接命令时收到错误消息。...
import pysftp
cnopts = pysftp.CnOpts()
cnopts.hostkeys = None # disable host key checking.
#with pysftp.Connection('test.rebex.net', username='demo',password='password', cnopts=cnopts) as sftp:
# do stuff here
# print('this works!')
s = pysftp.Connection(host='test.rebex.net', username='demo', password='password', cnopts=cnopts)
data = s.listdir()
s.close()
for i in data:
print (i)
我收到的错误是...
Unknown exception: from_buffer() cannot return the address of the raw string within a bytes or unicode object
Traceback (most recent call last):
File "/databricks/python/lib/python3.5/site-packages/paramiko/transport.py", line 2075, in run
self.kex_engine.parse_next(ptype, m)
File "/databricks/python/lib/python3.5/site-packages/paramiko/kex_curve25519.py", line 64, in parse_next
return self._parse_kexecdh_reply(m)
File "/databricks/python/lib/python3.5/site-packages/paramiko/kex_curve25519.py", line 129, in _parse_kexecdh_reply
self.transport._activate_outbound()
File "/databricks/python/lib/python3.5/site-packages/paramiko/transport.py", line 2553, in _activate_outbound
self.local_cipher, key_out, IV_out, self._ENCRYPT
File "/databricks/python/lib/python3.5/site-packages/paramiko/transport.py", line 1934, in _get_cipher
return cipher.encryptor()
File "/databricks/python/lib/python3.5/site-packages/cryptography/hazmat/primitives/ciphers/base.py", line 121, in encryptor
self.algorithm, self.mode
File "/databricks/python/lib/python3.5/site-packages/cryptography/hazmat/backends/openssl/backend.py", line 298, in create_symmetric_encryption_ctx
return _CipherContext(self, cipher, mode, _CipherContext._ENCRYPT)
File "/databricks/python/lib/python3.5/site-packages/cryptography/hazmat/backends/openssl/ciphers.py", line 67, in __init__
iv_nonce = self._backend._ffi.from_buffer(mode.nonce)
TypeError: from_buffer() cannot return the address of the raw string within a bytes or unicode object
TypeError: from_buffer() cannot return the address of the raw string within a bytes or unicode object
感谢您的帮助!
答案 0 :(得分:0)
pysftp
将paramiko
列为one of its dependencies。 Paramiko issue #1037文档并将代码中引发的错误归因于cryptography
的版本兼容性问题。
为避免这种情况,我的建议如下:
cryptography=2.6.1
conda env中包含了databricks-standard
的条件下进行测试)