我正在预测花朵的图像标签。我正在通过argparser将图像的路径作为参数传递。但是我遇到了以下错误。
我该如何解决?
functions-samples
thumbnailGeneratorSharp: async (object) => {
const fileBucket = object.bucket; // The Storage bucket that contains the file.
const filePath = object.name; // File path in the bucket.
const contentType = object.contentType; // File content type.
// Exit if this is triggered on a file that is not an image.
if (!contentType.startsWith('image/')) {
console.log('This is not an image.');
return null;
}
// Get the file name.
const fileName = path.basename(filePath);
// Exit if the image is already a thumbnail.
if (fileName.startsWith('thumb_')) {
console.log('Already a Thumbnail.');
return null;
}
// Download file from bucket.
const bucket = gcs.bucket(fileBucket);
const metadata = {
contentType: contentType,
};
// We add a 'thumb_' prefix to thumbnails file name. That's where we'll upload the thumbnail.
const thumbFileName = `thumb_${fileName}`;
const thumbFilePath = path.join(path.dirname(filePath), thumbFileName);
// Create write stream for uploading thumbnail
const thumbnailUploadStream = bucket.file(thumbFilePath).createWriteStream({ metadata });
// Create Sharp pipeline for resizing the image and use pipe to read from bucket read stream
const pipeline = sharp();
pipeline.resize(THUMB_MAX_WIDTH, THUMB_MAX_HEIGHT).max().pipe(thumbnailUploadStream);
bucket.file(filePath).createReadStream().pipe(pipeline);
return new Promise((resolve, reject) =>
thumbnailUploadStream.on('finish', resolve).on('error', reject));
}
答案 0 :(得分:0)
在将参数nargs=1
添加到参数解析器时,您可能设置了input_img
。
像这样:
parser.add_argument('--input_img', type=open, nargs=1)
来自docs:
请注意,nargs = 1会产生一项的列表。这不同于 默认情况下,商品是由其自身生产的。
只需删除nargs
:
parser.add_argument('--input_img', type=open)