如何使用Java加密和PHP解密?

时间:2019-08-13 23:26:03

标签: java php encryption

我有一个旧脚本,该脚本已经将加密数据保存到数据库中。

使用以下代码使用Java进行加密/解密。

public class StringEncrypter {

    Cipher ecipher;
    Cipher dcipher;

    /**
     * Constructor used to create this object. Responsible for setting and
     * initializing this object's encrypter and decrypter Chipher instances
     * given a Pass Phrase and algorithm.
     * 
     * @param passPhrase
     *            Pass Phrase used to initialize both the encrypter and
     *            decrypter instances.
     */
    public StringEncrypter(String passPhrase) {

        // 8-bytes Salt
        byte[] salt = { (byte) 0xA9, (byte) 0x9B, (byte) 0xC8, (byte) 0x32,
                (byte) 0x56, (byte) 0x34, (byte) 0xE3, (byte) 0x03 };

        // Iteration count
        int iterationCount = 19;

        try {

            KeySpec keySpec = new PBEKeySpec(passPhrase.toCharArray(), salt,
                    iterationCount);
            SecretKey key = SecretKeyFactory.getInstance("PBEWithMD5AndDES")
                    .generateSecret(keySpec);

            ecipher = Cipher.getInstance(key.getAlgorithm());
            dcipher = Cipher.getInstance(key.getAlgorithm());

            // Prepare the parameters to the cipthers
            AlgorithmParameterSpec paramSpec = new PBEParameterSpec(salt,
                    iterationCount);

            ecipher.init(Cipher.ENCRYPT_MODE, key, paramSpec);
            dcipher.init(Cipher.DECRYPT_MODE, key, paramSpec);

        } catch (InvalidAlgorithmParameterException e) {
            System.out.println("EXCEPTION: InvalidAlgorithmParameterException");
        } catch (InvalidKeySpecException e) {
            System.out.println("EXCEPTION: InvalidKeySpecException");
        } catch (NoSuchPaddingException e) {
            System.out.println("EXCEPTION: NoSuchPaddingException");
        } catch (NoSuchAlgorithmException e) {
            System.out.println("EXCEPTION: NoSuchAlgorithmException");
        } catch (InvalidKeyException e) {
            System.out.println("EXCEPTION: InvalidKeyException");
        }
    }

    /**
     * Takes a single String as an argument and returns an Encrypted version of
     * that String.
     * 
     * @param str
     *            String to be encrypted
     * @return <code>String</code> Encrypted version of the provided String
     */
    public String encrypt(String str) {
        try {
            // Encode the string into bytes using utf-8
            byte[] utf8 = str.getBytes("UTF8");

            // Encrypt
            byte[] enc = ecipher.doFinal(utf8);

            // Encode bytes to base64 to get a string
            return new sun.misc.BASE64Encoder().encode(enc);

        } catch (BadPaddingException e) {
        } catch (IllegalBlockSizeException e) {
        } catch (UnsupportedEncodingException e) {
        } catch (IOException e) {
        }
        return null;
    }

    /**
     * Takes a encrypted String as an argument, decrypts and returns the
     * decrypted String.
     * 
     * @param str
     *            Encrypted String to be decrypted
     * @return <code>String</code> Decrypted version of the provided String
     */
    public String decrypt(String str) {

        try {

            // Decode base64 to get bytes
            byte[] dec = new sun.misc.BASE64Decoder().decodeBuffer(str);

            // Decrypt
            byte[] utf8 = dcipher.doFinal(dec);

            // Decode using utf-8
            return new String(utf8, "UTF8");

        } catch (BadPaddingException e) {
        } catch (IllegalBlockSizeException e) {
        } catch (UnsupportedEncodingException e) {
        } catch (IOException e) {
        }
        return null;
    }
}

这会将一个字符串像这样RX0qxgKAKmjQmS9xjNtFnw==

放入数据库中

我需要能够使用PHP解密此数据。

我尝试从github使用以下脚本: https://github.com/KevinBusse/PBEWithMD5AndDES

但是只能得到bad magic number

的输出

这可能吗?如果是这样,任何方向将不胜感激!

1 个答案:

答案 0 :(得分:1)

如果从Java代码获取以下设置,则可以使用Github代码进行解密:

  • 盐(十六进制):A99BC8325634E303
  • 迭代次数:19

示例:

Passphrase:                    MyPassphraseXYZ
Plaintext:                     The quick brown fox jumps over the lazy dog
Ciphertext from the Java code: xWnsqJJ4pqWTrm8kIwfyw1djD4lu0zig0wnohS+EtwDvHBgEP/BS25qyaE+QEdxd

密文可以使用以下PHP代码解密:

$data = "xWnsqJJ4pqWTrm8kIwfyw1djD4lu0zig0wnohS+EtwDvHBgEP/BS25qyaE+QEdxd";
$keystring = "MyPassphraseXYZ";
$salt = "A99BC8325634E303";
$iterationsMd5 = 19; 
$decrypted = PbeWithMd5AndDes::decrypt($data, $keystring, $salt, $iterationsMd5);
print($decrypted . "\n");

必须考虑以下因素:PbeWithMd5AndDes已经过时,并且已经使用了多年,请参阅here。 Github代码本身使用其他已弃用的函数,例如mcrypt_module_XXX()mcrypt_generic_YYY(),因此该代码只能在PHP <7.2以下的版本中执行。在PHP 7.1中,将显示已弃用的警告。仅对于PHP <7.1,该代码可以在没有警告的情况下执行。总而言之,算法和代码都是不安全的。