这里的问题是在客户端使用Apache HttpClient时使用具有NTLM身份验证的Web资源。我遇到的问题是强制客户端使用NTLM身份验证。这是一个代码sapmle。
DefaultHttpClient httpclient = new DefaultHttpClient();
httpclient.getAuthSchemes().register("ntlm",new NTLMSchemeFactory());
NTCredentials creds = new NTCredentials("_myUSer_","_myPass_","_myWorkstation_","_myDomain_");
httpclient.getCredentialsProvider().setCredentials( new AuthScope("serverName",80), creds);
List<String> authpref = new ArrayList<String>();
authpref.add(AuthPolicy.NTLM);
httpclient.getParams().setParameter(AuthPNames.PROXY_AUTH_PREF, authpref);
HttpHost target = new HttpHost("serverName", 80, "http");
HttpGet httpget = new HttpGet("webResource");
HttpContext localContext = new BasicHttpContext();
HttpResponse response = httpclient.execute(target, httpget, localContext);
以下是来自Java的错误:
org.apache.http.client.protocol.RequestTargetAuthentication process
SEVERE: Authentication error: Invalid name provided (Mechanism level: Could not load configuration file C:\WINDOWS\krb5.ini (The system cannot find the file specified))
Web服务器响应为401
。
有关为何未正确设置身份验证政策的任何想法? 我在代码中遗漏了什么吗?
答案 0 :(得分:5)
我有类似的情况,我怀疑你设置了错误的参数:AuthPNames.PROXY_AUTH_PREF。我使用AuthPNames.TARGET_AUTH_PREF,似乎一切正常。
答案 1 :(得分:2)
以下是我对这个问题的解决方案:“evandongen”是对的。
请注意使用URIBuilder。
String username = "uid";
String pwd = "pwd";
String servername = "www.someserver.com";
String workstation = "myworkstation";
String domain = "somedomain";
String relativeurl = "/util/myservice.asmx";
String oldimagePath = "\\mypath\\image.jpg";
DefaultHttpClient httpclient = new DefaultHttpClient();
try {
httpclient.getAuthSchemes().register("ntlm",new NTLMSchemeFactory());
NTCredentials creds = new NTCredentials(username,pwd,workstation,domain);
httpclient.getCredentialsProvider().setCredentials(new AuthScope(servername,80), creds);
List authpref = new ArrayList();
authpref.add(AuthPolicy.NTLM);
URIBuilder builder = new URIBuilder();
builder.setScheme("http")
.setHost(servername)
.setPath(relativeurl + "/DeleteImage")
.setParameter("imagePath", oldimagePath);
URI uri = builder.build();
httpclient.getParams().setParameter(AuthPNames.TARGET_AUTH_PREF, authpref);
HttpHost target = new HttpHost(servicename, 80, "http");
HttpGet httpget = new HttpGet(uri);
HttpContext localContext = new BasicHttpContext();
HttpResponse response1 = httpclient.execute(target, httpget, localContext);
BufferedReader reader = new BufferedReader(new InputStreamReader(response1.getEntity().getContent()));
String line = reader.readLine();
while (line != null)
{
System.out.println(line);
line = reader.readLine();
}
} catch (Exception e) {
System.out.println("Exception:"+e.toString());
} finally {
// End
}
答案 2 :(得分:0)
我认为这是因为缺陷,请参阅here。
答案 3 :(得分:0)
HttpClient对我不起作用,但下面的片段确实如此。 参考 - http://docs.oracle.com/javase/7/docs/technotes/guides/net/http-auth.html
public static String getResponse(String url, String userName, String password) throws IOException {
Authenticator.setDefault(new Authenticator() {
@Override
public PasswordAuthentication getPasswordAuthentication() {
System.out.println(getRequestingScheme() + " authentication");
return new PasswordAuthentication(userName, password.toCharArray());
}
});
URL urlRequest = new URL(url);
HttpURLConnection conn = (HttpURLConnection) urlRequest.openConnection();
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setRequestMethod("GET");
StringBuilder response = new StringBuilder();
InputStream stream = conn.getInputStream();
BufferedReader in = new BufferedReader(new InputStreamReader(stream));
String str = "";
while ((str = in.readLine()) != null) {
response.append(str);
}
in.close();
return response.toString();
}