如何从Mathematica访问StackOverflow API

时间：2011-04-21 14:13:11

标签： wolfram-mathematica

前几天我想知道StackOverflow是否有我可以从Mathematica访问的API，显然它确实如此："Saving plot annotations"

将StackOverflow中的数据导入Mathematica的最佳方法是什么？ Sjoerd利用这些信息制作了一个情节。我有兴趣将SO相关的通知添加到我保存在笔记本中的停靠单元格中，因此我可以在不离开Mathematica的情况下判断何时有更新或响应。

2 个答案:

答案 0 :(得分：26)

根据大众需求，使用annotations生成前10个SO回复者的代码（SO API除外）（这是一个非常整洁和完整的API;很多好东西。很容易 - 看我的代码）。

更新：添加App-key以确保代码与SO-API（每日通话上限更高）更好地合作。请仅在此应用中使用它。

2011年4月 enter image description here

2011年8月 enter image description here

MMA 8版！ MMA7版本进一步向下 

getRepChanges[userID_Integer] :=
 Module[{totalChanges},
  totalChanges = 
   "total" /. 
    Import["http://api.stackoverflow.com/1.1/users/" <> 
      ToString[userID] <> "/reputation?key=NgVJ4Y6vFkuF-oqI-eOvOw&fromdate=0&pagesize=1&page=1",
      "JSON"
    ];
    Join @@ 
    Table[
      "rep_changes" /. 
         Import["http://api.stackoverflow.com/1.1/users/" <> 
                ToString[userID] <> 
                "/reputation?key=NgVJ4Y6vFkuF-oqI-eOvOw&fromdate=0&pagesize=100&page=" 
                <> ToString[page], 
                "JSON"
         ],
         {page, 1, Ceiling[totalChanges/100]}
    ]
  ]

topAnswerers = 
  ({"display_name","user_id", "email_hash"} /. #) & /@ 
     ("user" /. 
      ("top_users" /. 
        Import[
          "http://api.stackoverflow.com/1.1/tags/mathematica/top-answerers/all-time",    
          "JSON"
        ]
       )
      )

topAnswerers = {#, #2, 
    Import["http://www.gravatar.com/avatar/" <> #3 <> ".jpg?s=36&d=identicon&d=identicon"]
    } & @@@ topAnswerers

repChangesTopUsers =
  Table[
    repChange = 
     ReleaseHold[
        (
         Hold[
           {
              DateList["on_date" + AbsoluteTime["January 1, 1970"]], 
             "positive_rep" - "negative_rep"
           }
         ] /. #
        ) & /@ getRepChanges[userID]
      ] // Sort;
      accRepChange = {repChange[[All, 1]],Accumulate[repChange[[All, 2]]]}\[Transpose],
      {userID, topAnswerers[[All, 2]]}
    ];

pl = DateListLogPlot[
  Tooltip @@@ 
   Take[({repChangesTopUsers, Row /@ topAnswerers[[All, {3, 1}]]}\[Transpose]), 
    10], Joined -> True, Mesh -> None, ImageSize -> 1000, 
  PlotRange -> {All, {10, All}}, 
  BaseStyle -> {FontFamily -> "Arial-Bold", FontSize -> 16}, 
  DateTicksFormat -> {"MonthNameShort", " ", "Year"}, 
  GridLines -> {True, None}, 
  FrameLabel -> (Style[#, FontSize -> 18] & /@ {"Date", "Reputation", 
      "Top-10 answerers", ""})]

修改
请注意，您可以通过更改Take功能中的值来绘制最多20个并包括前20个。很快就会很忙。

试图在某种程度上提高标记代码的可读性。我担心这会在复制时产生一些假的空间。

修改
页面大小返回100个元素/页面==＆gt;更少的API调用 请注意，首次调用API是为了确定用户拥有的帖子数量。无论页面大小如何，都存在该数据，因此优选地选择较小（大约10个，可能是1个，不检查）。然后在连续页面中获取数据，直到到达最后一页。您可以使用最大页面大小（100）。请注意调整循环计数中的最大页数。

编辑：更好的MMA 7代码（4月22日星期五）

MMA 7不进行JSON导入，因此我执行文本导入，然后进行简单的JSON转换。我现在已经多次测试过这个版本（在MMA 8中），它似乎没有我昨天得到的错误。 

getRepChanges[userID_Integer] :=
 Module[{totalChanges},
  totalChanges = 
   "total" /. 
    ImportString[
     StringReplace[(Import[
        "http://api.stackoverflow.com/1.1/users/" <> 
         ToString[userID] <> 
         "/reputation?key=NgVJ4Y6vFkuF-oqI-eOvOw&fromdate=0&pagesize=1&page=1", "Text"]), {":" ->
         "->", "[" -> "{", "]" -> "}"}], "NB"];
  Join @@ 
   Table["rep_changes" /. 
     ImportString[
      StringReplace[
       Import["http://api.stackoverflow.com/1.1/users/" <> 
         ToString[userID] <> 
         "/reputation?key=NgVJ4Y6vFkuF-oqI-eOvOw&fromdate=0&pagesize=100&page=" <> ToString[page],
         "Text"], {":" -> "->", "[" -> "{", "]" -> "}"}], 
      "NB"], {page, 1, Ceiling[totalChanges/100]}]]
topAnswerers = ({"display_name", "user_id", 
      "email_hash"} /. #) & /@ ("user" /. ("top_users" /. 
      ImportString[
       StringReplace[
        " " <> Import[
          "http://api.stackoverflow.com/1.1/tags/mathematica/top-answerers/all-time", "Text"], {":" -> "->", "[" -> "{", "]" -> "}"}], 
       "NB"]))
topAnswerers = {#, #2, 
    Import["http://www.gravatar.com/avatar/" <> #3 <> 
      ".jpg?s=36&d=identicon&d=identicon"]} & @@@ topAnswerers
repChangesTopUsers = 
  Table[repChange = 
    ReleaseHold[(Hold[{DateList[
             "on_date" + AbsoluteTime["January 1, 1970"]], 
            "positive_rep" - "negative_rep"}] /. #) & /@ 
       getRepChanges[userID]] // Sort;
   accRepChange = {repChange[[All, 1]], 
      Accumulate[repChange[[All, 2]]]}\[Transpose], {userID, 
    topAnswerers[[All, 2]]}];

DateListLogPlot[
 Tooltip @@@ 
  Take[({repChangesTopUsers, 
      Row /@ topAnswerers[[All, {3, 1}]]}\[Transpose]), 10], 
 Joined -> True, Mesh -> None, ImageSize -> 1000, 
 PlotRange -> {All, {10, All}}, 
 BaseStyle -> {FontFamily -> "Arial-Bold", FontSize -> 16}, 
 DateTicksFormat -> {"MonthNameShort", " ", "Year"}, 
 GridLines -> {True, None}, 
 FrameLabel -> (Style[#, FontSize -> 18] & /@ {"Date", "Reputation", 
     "Top-10 answerers", ""})]

编辑：过滤帖子标签的辅助功能 这些函数可用于过滤信誉增益，以便仅查找某些标记的增益。 tagLookup获取post_ID整数作为输入，并生成特定帖子的标签。 getQuestionIDs和getAnswerIDsFrom...走另一条路。给定标记后，他们会找到所有问题和答案ID，以便可以使用MemberQ测试给定的post_ID是否属于此标记。 tagLookup和getAnswerID都很慢，因为许多API调用都是必需的。我无法测试最后两个函数，因为API访问已关闭或我的IP已被限制。

tagLookup[postID_Integer] :=
 Module[{im},
  im = Import["http://api.stackoverflow.com/1.1/questions/" <> ToString[postID],"JSON"];
  If[("questions" /. im) != {},
   First[("tags" /. ("questions" /. im))],
   im = Import["http://api.stackoverflow.com/1.1/answers/" <> ToString[postID],"JSON"];
   First[("tags" /. ("questions" /. Import["http://api.stackoverflow.com/1.1/questions/" <> 
          ToString[First["question_id" /. ("answers" /. im)]], "JSON"]))]
   ]
  ]

getQuestionIDs[tagName_String] := Module[{total},
  total = 
   "total" /. 
    Import["http://api.stackoverflow.com/1.1/questions?tagged=" <> 
      tagName <> "&pagesize=1", "JSON"];
  Join @@ 
   Table[("question_id" /. ("questions" /. 
        Import["http://api.stackoverflow.com/1.1/questions?key=NgVJ4Y6vFkuF-oqI-eOvOw&tagged=" <>
           tagName <> "&pagesize=100&page=" <> ToString[i], 
         "JSON"])), {i, 1, Ceiling[total/100]}]
  ]

getAnswerIDsFromQuestionID[questionID_Integer] :=
 Module[{total},
  total = 
   Import["http://api.stackoverflow.com/1.1/questions/" <> 
     ToString[questionID] <> "/answers?key=NgVJ4Y6vFkuF-oqI-eOvOw&pagesize=1", "JSON"];
  If[total === $Failed, Return[$Failed], total = "total" /. total]; 
  Join @@ Table[
    "answer_id" /. ("answers" /. 
       Import["http://api.stackoverflow.com/1.1/questions/" <> 
         ToString[questionID] <> "/answers?key=NgVJ4Y6vFkuF-oqI-eOvOw&pagesize=100&page=" <> 
         ToString[i], "JSON"]), {i, 1, Ceiling[total/100]}]
  ]

getAnswerIDsFromTag[tagName_String] :=
 Module[{},
  Join @@ (getAnswerIDsFromQuestionID /@ 
     Cases[getQuestionIDs[tagName], Except[$Failed]])
  ]

答案 1 :(得分：12)

Brett，与SO API无关，但您可以使用RSS提要来获取最新的Mathematica标记问题。这是我的天真实施：

QuestionHyperlink[data_] := 
 Function[{name, title, link}, 
   Hyperlink[Tooltip[title, name], link]] @@ Join[
   Cases[data, 
    XMLElement[
      "author", _, {___, XMLElement["name", {}, {name_}], ___}] :> 
     name],
   Cases[data, XMLElement["title", _, {title_}] :> title],
   Cases[data, XMLElement["link", rules_, {}] :> ("href" /. rules)]]

Cases[Import[
  "http://stackoverflow.com/feeds/tag?tagnames=mathematica&sort=\
newest", "XML"], 
 XMLElement["entry", attrs_, data_] :> 
  QuestionHyperlink[data], Infinity]

enter image description here

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