我有JSON:
{"jobs":[{"name":"PR-BVT","lastBuild":{"result":"SUCCESS","timestamp":1303358462150}},{"name":"PR-DBT-MYSQL","lastBuild":{"result":"SUCCESS","timestamp":1302057202000}},{"name":"PR-DBT-POSTGRESQL","lastBuild":{"result":"SUCCESS","timestamp":1302057202000}},{"name":"PR-FUNCT","lastBuild":{"result":"SUCCESS","timestamp":1303358496244}},{"name":"PR-LOADT","lastBuild":{"result":"SUCCESS","timestamp":1302057202000}},{"name":"PR-MAIN","lastBuild":{"result":"UNSTABLE","timestamp":1303358515506}},{"name":"PR-SECT","lastBuild":{"result":"SUCCESS","timestamp":1302057211000}},{"name":"PR-WEB-BVT","lastBuild":{"result":"SUCCESS","timestamp":1303358471795}},{"name":"praefectus-qa","lastBuild":{"result":"FAILURE","timestamp":1303358496583}},{"name":"praefectus_main","lastBuild":{"result":"FAILURE","timestamp":1303358476843}},{"name":"praefectus_today","lastBuild":{"result":"FAILURE","timestamp":1303358477786}},{"name":"prefectus-qa-1","lastBuild":{"result":"FAILURE","timestamp":1303358480424}},{"name":"pygments","lastBuild":{"result":"SUCCESS","timestamp":1303358482063}},{"name":"test-slave","lastBuild":{"result":"SUCCESS","timestamp":1302057202000}}]}
这是我从浏览器上的URL
获得的http://10.0.1.115:8080/api/json?tree=jobs[name,lastBuild[timestamp,result]]
我要做的是循环遍历该数据结构中的“jobs”并在drawChart函数中添加适当的行,即:
function drawChart() {
var data = new google.visualization.DataTable();
data.addColumn('datetime', 'Date');
data.addColumn('number', 'Builds Passed');
data.addColumn('string', 'title1');
data.addColumn('string', 'text1');
data.addColumn('number', 'Build Failed');
data.addColumn('string', 'title2');
data.addColumn('string', 'text2');
data.addRows([
[new Date(2011, 1 ,1), 30000, undefined, undefined, 40645, undefined, undefined],
[new Date(2011, 2 ,2), 14045, undefined, undefined, 20374, undefined, undefined],
[new Date(2011, 3 ,3), 55022, undefined, undefined, 50766, undefined, undefined],
[new Date(2011, 4 ,4), 75284, undefined, undefined, 14334, 'Lemco','Build Failed'],
[new Date(2011, 5 ,5), 41476, 'Build Passed','Tecore', 66467, undefined, undefined],
[new Date(2011, 6 ,6), 33322, undefined, undefined, 39463, undefined, undefined],
[new Date(2011, 7 ,6), 33322, undefined, undefined, 39463, undefined, undefined],
[new Date(2011, 8 ,6), 33322, undefined, undefined, 39463, undefined, undefined],
[new Date(2011, 9 ,6), 33322, undefined, undefined, 39463, undefined, undefined],
[new Date(2011, 10 ,6), 33322, undefined, undefined, 39463, undefined, undefined],
[new Date(2011, 11 ,6), 33322, undefined, undefined, 39463, undefined, undefined],
[new Date(2011, 12 ,6), 33322, undefined, undefined, 39463, undefined, undefined]
]);
任何想法如何?
答案 0 :(得分:0)
使用JSONP。
答案 1 :(得分:0)
嗯......问题并不是说数据来自不同的域。您可以使用JSON解析器(like this one)来解析您的JSON结果:
var jsonString = "/*your json here*/";
var result = JSON.parse(jsonString);
然后将result
传递给您的函数。结果将包含可用于访问数据的标准JavaScript数据结构。例如,
result.jobs[0].name //contains PR-BVT