函数replace（）似乎不起作用

Question

这是我的作业问题：

  

编写一系列语句，这些语句产生一个名为newA的副本，   其中字符“。”，“，”，“;”和“ \ n”已替换为   空格。

然后我使用了replace（）函数来执行此操作，但是当我执行newA时，输出是a，而不是替换。

这是我到目前为止所做的：

a = ' ' 'It was the best of times, it was the worst of times; it was the age of wisdom, it was the age of foolishness; it was the epoch of belief, it was the epoch of incredulity; it was ...' ' '

newA = a.replace('.', ' ')

newA = a.replace(',', ' ')

newA = a.replace(';', ' ')

newA = a.replace('\n', ' ')

为什么不起作用？如何使它起作用？

Answer 1

第一次使用newA是因为分配给newA的替换字符串是

newA = a.replace('.', ' ')
newA = newA.replace(',', ' ')
newA = newA.replace(';', ' ')

newA = newA.replace('\n', ' ')

Answer 2

您正在对原始字符串a进行操作。您需要将最后三个替换项从a.replace更改为newA.replace。

Answer 3

我认为您应该采用这种方式：

a = ' ' 'It was the best of times, it was the worst of times; it was the age of wisdom, it was the age of foolishness; it was the epoch of belief, it was the epoch of incredulity; it was ...' ' '

newA = a.replace('.', ' ')  
newA = newA.replace(',', ' ')    
newA = newA.replace(';', ' ')    
newA = newA.replace('\n', ' ')

或

a = ' ' 'It was the best of times, it was the worst of times; it was the age of wisdom, it was the age of foolishness; it was the epoch of belief, it was the epoch of incredulity; it was ...' ' '

newA = a.replace('.', ' ').replace(',', ' ').replace(';', ' ').replace('\n', ' ')

在您的示例中，您反复在初始'a'变量上使用replace。