我的问题是关于如何以传统的ICloneable
接口的方式实现这种方式,以便在将来的程序员不关注时不会导致意外的对象切片。这是我要检测的一种编程错误的示例(最好在编译时):
#include <stdio.h>
class ICloneable
{
public:
virtual ICloneable * clone() const = 0;
};
class A : public ICloneable
{
public:
A() {}
A(const A & rhs) {}
virtual ICloneable * clone() const {return new A(*this);}
};
class B : public A
{
public:
B() {}
B(const B & rhs) {}
// Problem, B's programmer forget to add a clone() method here!
};
int main(int, char**)
{
B b;
ICloneable * clone = b.clone(); // d'oh! (clone) points to an A, not a B!
return 0;
}
如果B
(或B
的任何其他非抽象子类)未定义自己的clone()
方法,C ++中是否有任何方法可以说服编译器发出错误消息?简而言之,是否有任何自动方法可以在运行时检测此错误?
答案 0 :(得分:1)
前一段时间,我在相同的情况下面临着同样的问题,而没有找到令人满意的解决方案。
再次考虑这一点,我发现可能是一个解决方案(充其量):
#include <iostream>
#include <typeinfo>
#include <typeindex>
class Base { // abstract
protected:
Base() = default;
Base(const Base&) = default;
Base& operator=(const Base&) = default;
public:
virtual ~Base() = default;
Base* clone() const
{
Base *pClone = this->onClone();
const std::type_info &tiClone = typeid(*pClone);
const std::type_info &tiThis = typeid(*this);
#if 0 // in production
assert(std::type_index(tiClone) == type_index(tiThis),
"Missing overload of onClone()!");
#else // for demo
if (std::type_index(tiClone) != std::type_index(tiThis)) {
std::cout << "ERROR: Missing overload of onClone()!\n"
<< " in " << tiThis.name() << '\n';
}
#endif // 0
return pClone;
}
protected:
virtual Base* onClone() const = 0;
};
class Instanceable: public Base {
public:
Instanceable() = default;
Instanceable(const Instanceable&) = default;
Instanceable& operator=(const Instanceable&) = default;
virtual ~Instanceable() = default;
protected:
virtual Base* onClone() const { return new Instanceable(*this); }
};
class Derived: public Instanceable {
public:
Derived() = default;
Derived(const Derived&) = default;
Derived& operator=(const Derived&) = default;
virtual ~Derived() = default;
protected:
virtual Base* onClone() const override { return new Derived(*this); }
};
class WrongDerived: public Derived {
public:
WrongDerived() = default;
WrongDerived(const WrongDerived&) = default;
WrongDerived& operator=(const WrongDerived&) = default;
virtual ~WrongDerived() = default;
// override missing
};
class BadDerived: public Derived {
public:
BadDerived() = default;
BadDerived(const BadDerived&) = default;
BadDerived& operator=(const BadDerived&) = default;
virtual ~BadDerived() = default;
// copy/paste error
protected:
virtual Base* onClone() const override { return new Derived(*this); }
};
#define DEBUG(...) std::cout << #__VA_ARGS__ << ";\n"; __VA_ARGS__
int main()
{
DEBUG(Instanceable obj1);
DEBUG(Base *pObj1Clone = obj1.clone());
DEBUG(std::cout << "-> " << typeid(*pObj1Clone).name() << "\n\n");
DEBUG(Derived obj2);
DEBUG(Base *pObj2Clone = obj2.clone());
DEBUG(std::cout << "-> " << typeid(*pObj2Clone).name() << "\n\n");
DEBUG(WrongDerived obj3);
DEBUG(Base *pObj3Clone = obj3.clone());
DEBUG(std::cout << "-> " << typeid(*pObj3Clone).name() << "\n\n");
DEBUG(BadDerived obj4);
DEBUG(Base *pObj4Clone = obj4.clone());
DEBUG(std::cout << "-> " << typeid(*pObj4Clone).name() << "\n\n");
}
输出:
Instanceable obj1;
Base *pObj1Clone = obj1.clone();
std::cout << "-> " << typeid(*pObj1Clone).name() << '\n';
-> 12Instanceable
Derived obj2;
Base *pObj2Clone = obj2.clone();
std::cout << "-> " << typeid(*pObj2Clone).name() << '\n';
-> 7Derived
WrongDerived obj3;
Base *pObj3Clone = obj3.clone();
Missing overload of onClone()!
ERROR: Missing overload of onClone()!
in 12WrongDerived
std::cout << "-> " << typeid(*pObj3Clone).name() << '\n';
-> 7Derived
BadDerived obj4;
Base *pObj4Clone = obj4.clone();
Missing overload of onClone()!
ERROR: Missing overload of onClone()!
in 10BadDerived
std::cout << "-> " << typeid(*pObj4Clone).name() << '\n';
-> 7Derived
这个技巧实际上很简单:
它不是取代clone()
本身,而是用作蹦床virtual onClone()
方法中。因此,clone()
可以在返回结果之前检查结果的正确性。
这不是编译时检查,而是运行时检查(我认为是第二好的选择)。假设希望至少在开发期间检查/调试开发中的类库的每个类,我都会发现这是相当可靠的。
答案 1 :(得分:0)
不要使A和B继承自IClonable。使用包装器(BluePrint)代替:
"Hello {}".format(
您将不得不稍微修改一下代码,因为这将返回包装的克隆,而不是立即返回要克隆的元素的克隆。再说一次,我不知道您打算如何使用IClonable接口,因此我无法为您完成此示例。