我试图运行基于以下链接的代码
https://documen.tician.de/pycuda/tutorial.html
在此链接中运行代码原来很好。
这是我的版本,具有类似的定义。请注意,由于要运行engine.execute函数,因此我在引擎上下文中运行。
import pycuda.driver as cuda
import pycuda.autoinit
import tensorrt as trt
import numpy as np
from keras.datasets import mnist
dims = (1, 28, 28)
dims2 = (1, 1, 10)
batch_size = 1000
nbytes = batch_size * trt.volume(dims) * np.dtype(np.float32).itemsize
nbytes2 = batch_size * trt.volume(dims2) * np.dtype(np.float32).itemsize
self.d_src = cuda.mem_alloc(nbytes)
self.d_dst = cuda.mem_alloc(nbytes2)
bindings = [int(self.d_src), int(self.d_dst)]
(x_train, y_train), (x_test, y_test) = mnist.load_data()
img_h = x_test.shape[1]
img_w = x_test.shape[2]
x_test = x_test.reshape(x_test.shape[0], 1, img_h, img_w)
x_test = x_test.astype('float32')
x_test /= 255
num_test = x_test.shape[0]
output_size = batch_size * trt.volume(dims2)
y = np.empty((num_test,output_size), np.float32)
for i in range(0, num_test, batch_size):
x_part = x_test[i : i + batch_size]
y_part = y[i : i + batch_size]
cuda.memcpy_htod(self.d_src, x_part)
cuda.memcpy_dtoh(y_part, self.d_dst)
但是它在memcpydtoh失败了,但memcpyhtod起作用了。
File "a.py", line 164, in infer
cuda.memcpy_dtoh(y_part, self.d_dst)
pycuda._driver.LogicError: cuMemcpyDtoH failed: invalid argument
为什么会这样?这些定义类似于链接中的代码。
答案 0 :(得分:1)
我已经解决了。
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<DataGrid Name="PlanGrid" HorizontalAlignment="Stretch" FontSize="16" RowHeight="30" HorizontalScrollBarVisibility="Visible"
VerticalAlignment="Stretch"
AutoGenerateColumns="True"
SelectionMode="Extended"
VerticalGridLinesBrush="Transparent"
Background="Transparent" RowBackground="Transparent"
ItemsSource="{Binding PlanDataView, Mode=TwoWay}"
IsReadOnly="True" SelectionUnit="FullRow" IsSynchronizedWithCurrentItem="True" Cursor="Arrow" AllowDrop="True">
<DataGrid.InputBindings>
<KeyBinding Gesture="Ctrl" Command="ApplicationCommands.NotACommand"></KeyBinding>
</DataGrid.InputBindings>
<i:Interaction.Triggers>
<i:EventTrigger EventName="Loaded">
<ei:CallMethodAction MethodName="PlanGrid_Loaded" TargetObject="{Binding}"></ei:CallMethodAction>
</i:EventTrigger>
</i:Interaction.Triggers>
</DataGrid>
和x_part
的设备分配必须不同,因为它们的大小不同。
因此,如果我定义y_part
,它就可以工作。
该错误消息对于以&开头不是很有帮助,并让我认为我输入了错误的参数。