Question

我想我创建了一个文件上传到数据库并从数据库系统显示。在此文件上传系统中，我可以上传图像。但是视频没有被上传。上传视频和图像该怎么办？

    <?php
$msg="";
if(isset($_POST['submit'])){
    $target = "images/".basename($_FILES['image']['name']);
    $db = mysqli_connect('localhost','root', '', 'prac');
    $topic=$_POST['topic'];
    $text=$_POST['caption'];
    $image=$_FILES['image']['name'];

    $sql= "INSERT INTO post(topic, caption, image) VALUES ('$topic', '$text', '$image')";
    mysqli_query($db, $sql);


    if(move_uploaded_file($_FILES['image']['tmp_name'],$target)){
        $msg="Image Uploaded";
    }
    else{
        $msg="Problem uploading image";
    }

}
?>

<?php echo $msg ?>
<div id="content">
<form method="POST" action="prac.php" enctype="multipart/form-data">
<input type="hidden" name="size" value="100000">
<select name="topic" required>
    <option></option>
  <option value="volvo">Volvo</option>
  <option value="saab">Saab</option>
  <option value="opel">Opel</option>
  <option value="audi">Audi</option>
</select>
<input type="text" name="caption" placeholder="caption">
<input type="file" name="image">
<button type="submit" name="submit">POST </button>
</form>

<?php
$db = mysqli_connect('localhost','root', '', 'prac');
$sql = "SELECT * FROM post";
$result= mysqli_query($db, $sql);
while ($row = mysqli_fetch_array($result)){
    echo "<tr>"."<img src='images/".$row['image']."' height='300px' max-width='100%'>"."</tr>";
    echo "<tr>"."<p>".$row['caption']."</p>"."</tr>";
}
?>

Answer 1

将此代码用于带有验证的视频和图像上传。

using System;
using System.Text;
using System.Xml;
using Microsoft.Extensions.Logging;

public static void Run(string myIoTHubMessage, out object outputDocument, 
ILogger log)
{
StringBuilder output = new StringBuilder();

if(myIoTHubMessage.Contains("Root"))
{
    output.Append("<?xml version='1.0' encoding='UTF-8'?><text>" + 
    myIoTHubMessage + "</text>");
}


string returnstring = output.ToString();
    if(returnstring.Contains("xml"))
    {
        XmlDocument returnXml = new XmlDocument();
        returnXml.LoadXml(returnstring);
        outputDocument = new 
        {
        returnXml
        };
    }
    else
    {
        outputDocument = new
        {
            myIoTHubMessage
        };
    }

为什么不使用此文件上传系统上传视频？（可以上传图片）。

1 个答案: