我正在尝试使用jpql和JPA来获取配置文件的配置文件菜单。我的“个人资料”和“ ProfileMenus”实体之间存在多对一的关系。
我尝试研究这些答案,但找不到任何可行的解决方案。
How to add non-standardized sql functions in Spring Boot application?
Registering a SQL function with JPA and Hibernate
我也通过此链接,似乎和我的问题相同, https://vladmihalcea.com/hibernate-sql-function-jpql-criteria-api-query/
使用本机查询时,我可以使用以下查询获取数据:
ProjectPath\android\app\
上面的查询为我提供了数据,
"SELECT
GROUP_CONCAT(pm.user_menu_id SEPARATOR ',')
AS profile_menu_ids,
p.description
FROM profile p
LEFT JOIN profile_menu pm ON p.id = pm.profile_id
WHERE
p.id =:profileId
AND
pm.status = 'Y'
GROUP BY p.id"
使用JPA的jpql中是否有任何方法或替代方法来获得如上所述的结果?
答案 0 :(得分:0)
您可以考虑使用FluentJPA,它支持任何自定义功能:
public ProfileMenuGroup getMenuIdsByProfile(int profileId) {
FluentQuery query = FluentJPA.SQL((Profile p,
ProfileMenu pm) -> {
String menuIds = alias(GROUP_CONCAT(pm.getUserMenuId(), ","),
ProfileMenuGroup::getProfileMenuIds);
String description = alias(p.getDescription(), ProfileMenuGroup::getDescription);
SELECT(menuIds, description);
FROM(p).LEFT_JOIN(pm).ON(p == pm.getProfile());
WHERE(p.getId() == profileId && pm.getStatus() == "Y");
GROUP(BY(p.getId()));
});
return query.createQuery(em, ProfileMenuGroup.class).getSingleResult();
}
查询产生以下SQL(profileId
是自动绑定的):
SELECT GROUP_CONCAT(t1.user_menu_id SEPARATOR ',') AS profile_menu_ids,
t0.description AS description
FROM profile t0 LEFT JOIN profile_menu t1 ON (t0.id = t1.profile_id)
WHERE ((t0.id = ?1) AND (t1.status = 'Y'))
GROUP BY t0.id
给出以下类型声明:
@Entity
@Data // lombok
@Table(name = "profile")
public class Profile {
@Id
private int id;
private String description;
}
@Entity
@Data // lombok
@Table(name = "profile_menu")
public class ProfileMenu {
@Id
private int id;
@ManyToOne
@JoinColumn(name = "profile_id")
private Profile profile;
private int userMenuId;
private String status;
}
@Tuple
@Data // lombok
public class ProfileMenuGroup {
private String profileMenuIds;
private String description;
}