我有一个<a href="~/YourControllerName/OnGetDelete?id=@item.id" id="deleteBtn" class="btn bg-danger mr-1" onclick="return confirm('Are you sure you want to delete?');"><i class="fas fa-trash-alt text-white"></i>Delete</a>
的数组，如果import matplotlib.pyplot as plt
plt.show()
$list这是我想要实现的结果数组结构（JSON）（请注意，最外面的文件夹print_r($list);是固定的）：
Array
(
[0] => images/announcement
[1] => images/background
[2] => images/background/thumbnail
[3] => images/character
[4] => images/character/frame
[5] => images/character/party
[6] => images/particle
[7] => images/story/background
[8] => images/story/character/1016/face
[9] => images/unit/thumbnail
[10] => images/user_title/background
[11] => ss/chapter_background
[12] => ss/others/ability_board_s
[13] => ss/others/common/back-light-2
[14] => ss/others/common/back_light_s
使用一些代码，我能够将每个files字符串拆分为多维数组：
{
"name":"files",
"type":"folder",
"path":"files",
"items":[
{
"name":"images",
"type":"folder",
"path":"files\/images",
"items":[
"name":"announcement",
"type":"folder",
"path":"files\/images\/announcement",
"items":[]
]
},
{
"name":"ss",
"type":"folder",
"path":"files\/ss",
"items":[
"name":"others",
"type":"folder",
"path":"files\/ss\/others",
"items":[
"name":"sub",
"type":"folder",
"path":"files\/ss\/sub",
"items":[]
]
]
},
{
"name":"sound",
"type":"folder",
"path":"files\/sound",
"items":[
]
},
{
"name":"New folder (4)",
"type":"folder",
"path":"files\/New folder (4)",
"items":[
]
},
{
"name":"New folder (5)",
"type":"folder",
"path":"files\/New folder (5)",
"items":[
]
},
{
"name":"New folder (6)",
"type":"folder",
"path":"files\/New folder (6)",
"items":[
]
}
]
}
生成的$list看起来像这样：
function explodeToNestedArray($delimiter, $key, $dir)
{
$value = array();
$keys = explode($delimiter, $key, 2);
$value["name"]=$keys[0];
$value["type"]= "folder";
$value["path"]= $dir . "/" . $keys[0];
if ($keys[1] == null) $value["items"] = array();
else
$value["items"] = explodeToNestedArray("/", $keys[1], $dir . "/" . $keys[0]);
return $value;
}
$list2 = array();
foreach ($list as $value) {
$list2[] = explodeToNestedArray("/", $value, "");
}
print_r($list2);
如果子数组[“ item”]元素具有相同的$list2，我该如何合并它们在Array
(
[0] => Array
(
[name] => images
[type] => folder
[path] => /images
[items] => Array
(
[name] => announcement
[type] => folder
[path] => /images/announcement
[items] => Array
(
)
)
)
[1] => Array
(
[name] => images
[type] => folder
[path] => /images
[items] => Array
(
[name] => background
[type] => folder
[path] => /images/background
[items] => Array
(
)
)
)
[2] => Array
(
[name] => images
[type] => folder
[path] => /images
[items] => Array
(
[name] => background
[type] => folder
[path] => /images/background
[items] => Array
(
[name] => thumbnail
[type] => folder
[path] => /images/background/thumbnail
[items] => Array
(
)
)
)
)
[3] => Array
(
[name] => images
[type] => folder
[path] => /images
[items] => Array
(
[name] => character
[type] => folder
[path] => /images/character
[items] => Array
(
)
)
)
[4] => Array
(
[name] => images
[type] => folder
[path] => /images
[items] => Array
(
[name] => character
[type] => folder
[path] => /images/character
[items] => Array
(
[name] => frame
[type] => folder
[path] => /images/character/frame
[items] => Array
(
)
)
)
)
[5] => Array
(
[name] => images
[type] => folder
[path] => /images
[items] => Array
(
[name] => character
[type] => folder
[path] => /images/character
[items] => Array
(
[name] => party
[type] => folder
[path] => /images/character/party
[items] => Array
(
)
)
)
)
..........etc*
)
中，这样我才能得到所需的结果？
使用$list2最终将所有子数组分为不同的类型，名称，路径和项数组。
答案 0 :(得分：2)
我认为这可以满足您的需求。它遍历列表的每个元素，在输出数组的list元素中查找每个键。如果找不到，它将在输出中创建一个新条目。如果找到，则我们继续在树上向下确定在哪里添加键的下部。请注意，对于叶子元素，我们添加了type中的file，如果您希望将其设为folder，只需删除该行上的条件（即$element['type'] = 'folder';）。
$output = array('name' => 'files', 'type' => 'folder', 'path' => 'files', 'items' => array());
function explodeToNestedArray($delimiter, $key, &$output) {
$keys = explode($delimiter, $key, 2);
if (($k = array_search($keys[0], array_column($output['items'], 'name'))) === false) {
// need to create an element
$element = array('name' => $keys[0], 'path' => $output['path'] . "/{$keys[0]}", 'items' => array());
$element['type'] = (count($keys) == 1) ? 'file' : 'folder';
if (count($keys) == 2) explodeToNestedArray($delimiter, $keys[1], $element);
$output['items'][] = $element;
}
else {
// any children to add?
if (count($keys) == 2) {
explodeToNestedArray($delimiter, $keys[1], $output['items'][$k]);
// change the type to folder in case it was previously a leaf
$output['items'][$k]['type'] = 'folder';
}
}
}
foreach ($list as $node) {
explodeToNestedArray('/', $node, $output);
}
输出内容太长，无法在此处显示，但是您可以在此demo on 3v4l.org中看到它。
答案 1 :(得分：0)
稍等一下，请在评论中让我知道它是否有效，我将继续回答。
function explodeToNestedArray($delimiter, $list, $dir) {
$data = array();
foreach($list as $key) {
$value = array();
$keys = explode($delimiter, $key, 2);
$value["name"] = $keys[0];
$value["type"] = "folder";
$value["path"] = $dir . "/" . $keys[0];
$items = array($keys[1]);
$value["items"] = ($keys[1] == null ? array() : explodeToNestedArray("/", $items, $dir . "/" . $keys[0]));
if(!isset($data[$keys[0]])) $data[$keys[0]] = array();
$data[$keys[0]][] = $value;
}
return $data;
}
$list = explodeToNestedArray("/", $list, "");
print_r($list);