Question

我想对离实时绘制的GLSurfaceView触摸50至50英里处的区域进行截图。

准确地说，如果触摸区域的坐标为X = 50，Y = 50，我想捕获矩形内部的区域，该区域的大小为（X-50，Y-50），（X + 50，Y + 50）。

@Override
    public void onDrawFrame(GL10 unused)
    {
        render();

        if (!mInitialized) {
            // Only need to do this once
            mEffectContext = EffectContext.createWithCurrentGlContext();
            mInitialized = true;
        }
        if (saveFrame) {
            saveBitmap(takeScreenshot(unused));
        }

    }

 private void saveBitmap(Bitmap bitmap) {
        try {
            File f = new File(Environment.getExternalStorageDirectory(), "zoom.png");
            f.createNewFile();
            OutputStream outputStream = new FileOutputStream(f);
            bitmap.compress(Bitmap.CompressFormat.PNG, 100, outputStream);
            outputStream.close();


            DispChar.mimg_char_1_1.setImageBitmap(bitmap);


            Log.i("TAG", "SAVED");
        } catch (Exception e) {
            Log.e("TAG", e.toString(), e);
        }
    }

 public Bitmap takeScreenshot(GL10 mGL) {
        final int mWidth = RadarMainActivity.mGLSurfaceView.getWidth();
        final int mHeight = RadarMainActivity.mGLSurfaceView.getHeight();
        IntBuffer ib = IntBuffer.allocate(mWidth * mHeight);
        IntBuffer ibt = IntBuffer.allocate(mWidth * mHeight);
        mGL.glReadPixels(0, 0, mWidth, mHeight, GL10.GL_RGBA, GL10.GL_UNSIGNED_BYTE, ib);

        // Convert upside down mirror-reversed image to right-side up normal image.
        for (int i = 0; i < mHeight; i++) {
            for (int j = 0; j < mWidth; j++) {
                ibt.put((mHeight - i - 1) * mWidth + j, ib.get(i * mWidth + j));
            }
        }

        Bitmap mBitmap = Bitmap.createBitmap(mWidth, mHeight,Bitmap.Config.ARGB_8888);
        mBitmap.copyPixelsFromBuffer(ibt);
        return mBitmap;
    }

我们目前正在从这些来源捕获。我们如何解决此问题，以便仅捕获某些部分？

PS。来源是基于此站点上某人的来源。

捕获GLSurfaceView的特定区域

0 个答案: