我有一堆orderIds'1,18,1000,77 ......'我正在从nvarchar(8000)中撤回。我试图解析此字符串并将id放入临时表。有一种简单有效的方法吗?
要查看我解析的所有orderId的列表,我应该能够这样做:
select orderid from #temp
答案 0 :(得分:7)
给它一个机会。它会将CSV值拆分并加载到表变量中。
declare @string nvarchar(500)
declare @pos int
declare @piece nvarchar(500)
declare @strings table(string nvarchar(512))
SELECT @string = 'ABC,DEF,GHIJK,LMNOPQRS,T,UV,WXY,Z'
if right(rtrim(@string),1) <> ','
SELECT @string = @string + ','
SELECT @pos = patindex('%,%' , @string)
while @pos <> 0
begin
SELECT @piece = left(@string, (@pos-1))
--you now have your string in @piece
insert into @strings(string) values ( cast(@piece as nvarchar(512)))
SELECT @string = stuff(@string, 1, @pos, '')
SELECT @pos = patindex('%,%' , @string)
end
SELECT * FROM @Strings
从Raymond at CodeBetter找到并修改。
答案 1 :(得分:7)
通过数字表创建的最快方式:
--First build your numbers table via cross joins
select top 8000 ID=IDENTITY(int,1,1)
into numbers
from syscolumns s1
,syscolumns s2
,syscolumns s3
GO
--add PK
alter table numbers add constraint PK_numbers primary key clustered(ID);
GO
create table #temp(
ID int identity(1,1) primary key,
StringValues varchar(8000)
)
declare @orderIds varchar(8000)
set @orderIds = ',1, 18, 1000, 77, 99, 1000, 2, 4,'
insert into #temp(StringValues)
select substring(@orderIds,ID+1,charindex(',',@orderIds,ID+1)-ID-1)
from numbers where ID < len(@orderIds)and substring(@orderIds,ID,1) = ',';
根据以下文章,这是我多年来一直使用的一种很好的方法: http://www.sqlservercentral.com/articles/T-SQL/62867/
答案 2 :(得分:4)
CREATE TABLE #t (UserName VARCHAR(50))
DECLARE @sql VARCHAR(MAX)
SELECT @sql = 'INSERT INTO #t SELECT ''' + REPLACE(@UserList, ',', ''' UNION SELECT ''') + ''''
PRINT (@sql)
EXEC (@sql)
SELECT * FROM #t
IF OBJECT_ID('tempdb..#t') IS NOT NULL BEGIN DROP TABLE #t END
答案 3 :(得分:2)
这是一个User Defined函数,它返回一个带有Id的DataTable,您可以将其用于关节。 看看this article可以很好地解决这个问题。
CREATE FUNCTION ParamParserFn( @delimString varchar(255), @delim char(1))
RETURNS @paramtable
TABLE ( Id int )
AS BEGIN
DECLARE @len int,
@index int,
@nextindex int
SET @len = DATALENGTH(@delimString)
SET @index = 0
SET @nextindex = 0
WHILE (@len > @index )
BEGIN
SET @nextindex = CHARINDEX(@delim, @delimString, @index)
if (@nextindex = 0 ) SET @nextindex = @len + 2
INSERT @paramtable
SELECT SUBSTRING( @delimString, @index, @nextindex - @index )
SET @index = @nextindex + 1
END
RETURN
END
GO
答案 4 :(得分:1)
更改&gt; to&gt; =在以下代码中仅对带有一个逗号的输入正常工作。相信链接文章中的第一条评论。
WHILE (@len > @index )
BEGIN
SET @nextindex = CHARINDEX(@delim, @delimString, @index)