Python代码没有执行我认为应该做的事情

时间:2019-08-06 23:01:54

标签: python repl.it

我已经用条件语句编写了一些代码,但我认为它不应该发生什么事情。

我试图多次重写代码。

def main():
def enter():
  inputenter = input("Please enter a number. ")
  if inputenter in ("1", "2", "3", "4", "5"):
    getready()
  else:
    inputstartagain = input("Invalid Request") 
def getready():
  inputgetreadybrush = input("Did you brush your teeth? ")
  if inputgetreadybrush == "Yes" or "yes" or "y" or "Y":
    inputgetreadyshower = input("Did you shower? ")
    if inputgetreadyshower == "Yes" or "yes" or "y" or "Y":
      print("Your output is: I already got ready. ")
    elif inputgetreadyshower == "No" or "no" or "N" or "n":
      print("Your output is: Shower ")
    else:
      print("")
  elif inputgetreadybrush == "No" or "no" or "n" or "N":
    inputgetreadyshower1 = input("Did you shower? ")
    if inputgetreadyshower1 == "Yes" or "yes" or "Y" or "y":
      print("Your output is: Brush ")
    elif inputgetreadyshower1 == "No" or "no" or "n" or "N":
      print("Your output is: Brush and Shower ")
  else:
    print("")

main()

我希望(这些是if语句的答案)1,y,n的输出为“您的输出为:淋浴”,但实际输出为“您的输出为:我已经准备好了。”

3 个答案:

答案 0 :(得分:1)

不可能or这样的条件,例如inputgetreadybrush == "Yes" or "yes" or "y" or "Y":

这将永远是正确的。它被解释为(inputgetreadybrush == "Yes") or "yes" or "y" or "Y":

如果答案不是“是”,则下一次测试or 'yes'将被视为是。

最好写成:

inputgetreadybrush[0].lower() == 'y':

答案 1 :(得分:0)

为什么您要为一个简单的是/否答案写这么多字?

如果您仅尝试检查第一个字母,将会更容易。在这种情况下,您将看到答案的第一个字母是“ y ”还是“ n

例如,如果您具有 getready()函数,它将看起来更加清晰:

def getready():
    inputgetreadybrush = input("Did you brush your teeth? ")

    if inputgetreadybrush.lower()[:1] == "y":
        inputgetreadyshower = input("Did you shower? ")

        if inputgetreadyshower.lower()[:1] == "y":
              print("Your output is: I already got ready. ")

        else:
              print("Your output is: Shower ")

    elif inputgetreadybrush.lower()[:1] == "n":
        inputgetreadyshower1 = input("Did you shower? ")

        if inputgetreadyshower1.lower()[:1] == "y":
          print("Your output is: Brush ")

        else:
          print("Your output is: Brush and Shower ")

    # In case you want to truck if anithing else was press:
    else:
        print(f"What do you mean {inputgetreadybrush.lower()}? I do not understand...")

在这种情况下,人类将更容易更快地知道那里发生了什么。并且看起来会更游行:))

答案 2 :(得分:0)

将所有条件更改为正确的语法:

if (inputgetreadybrush == "Yes") or (inputgetreadybrush == "yes") or (inputgetreadybrush == "y") or (inputgetreadybrush == "Y"):

这解决了您所有的问题。