Question

我正在开发django-rest-framework API，在其中我对VectorWise数据库进行一些SQL查询和计算，并创建带有一些输入参数的响应。

起初我有这样的结构：

    response = {'Date': input_date,
                'Date comparable': date_comparable,
                'CA': {
                    'CA TTC (€)': ca_ttc_n,
                    'Rang magasin': rank,
                    'progression (%)': progression_percentage
                },
                'Nb art / pass caisse': {
                    'nombre': nb_art_pass_caiss,
                    'progression (%)': nb_art_pass_caiss_prog
                },
                'Panier': {
                    '(€)': panier,
                    'progression (%)': prog_panier}
                }

哪个工人还好，并给我回复。

然后，我试图像这样改善响应的代码结构和可读性：

    response = {'Date': input_date,
                'Comparable date': date_comparable,
                'Indicators': {
                    {"Name": "sales",
                     "Value": ca_ttc_n,
                     "Unit": currency,
                     "Rank": rank},
                    {"Name": "sales_progression",
                     "Value": progression_percentage,
                     "Unit": percentage,
                     "Rank": rank},
                    {"Name": "customer_items_number",
                     "Value": nb_art_pass_caiss,
                     "Unit": "Units",
                     "Rank": rank},
                    {"Name": "customer_items_number_progression",
                     "Value": nb_art_pass_caiss_prog,
                     "Unit": percentage,
                     "Rank": rank},
                    {"Name": "basket",
                     "Value": panier,
                     "Unit": currency,
                     "Rank": rank}
                }

另一方面，这会导致抛出TypeError错误

Traceback (most recent call last):
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\core\handlers\exception.py", line 34, in inner
    response = get_response(request)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\core\handlers\base.py", line 115, in _get_response
    response = self.process_exception_by_middleware(e, request)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\core\handlers\base.py", line 113, in _get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\views\decorators\csrf.py", line 54, in wrapped_view
    return view_func(*args, **kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\views\generic\base.py", line 71, in view
    return self.dispatch(request, *args, **kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework\views.py", line 495, in dispatch
    response = self.handle_exception(exc)
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework\views.py", line 455, in handle_exception
    self.raise_uncaught_exception(exc)
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework\views.py", line 466, in raise_uncaught_exception
    raise exc
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework\views.py", line 492, in dispatch
    response = handler(request, *args, **kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework_extensions\cache\decorators.py", line 49, in inner
    kwargs=kwargs,
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework_extensions\cache\decorators.py", line 68, in process_cache_response
    response = view_method(view_instance, request, *args, **kwargs)
  File "C:\Users\10124077\Projects\dataplatform--web--api\wdc\views.py", line 484, in get
    "Rank": rank}
TypeError: unhashable type: 'dict'

我尝试删除rank字段并进行一些操作以更好地理解该问题，但是由于它不断在响应正文的其他字段上引发TypeError，所以我没有设法做到！有帮助吗？

Answer 1

问题在于：

'Indicators': {
                {"Name": "sales",
                 "Value": ca_ttc_n,
                 "Unit": currency,
                 "Rank": rank},
                {"Name": "sales_progression",
                 "Value": progression_percentage,
                 "Unit": percentage,
                 "Rank": rank},
                {"Name": "customer_items_number",
                 "Value": nb_art_pass_caiss,
                 "Unit": "Units",
                 "Rank": rank},
                {"Name": "customer_items_number_progression",
                 "Value": nb_art_pass_caiss_prog,
                 "Unit": percentage,
                 "Rank": rank},
                {"Name": "basket",
                 "Value": panier,
                 "Unit": currency,
                 "Rank": rank}
            }

...尝试创建字典的集。因此，您的代码基本上是这样做的：

{{"this": "is", "a": "dictionary"}, {"within": "a set"}}

之所以无法做到这一点，是因为只能构造一组可哈希对象，而dict是不可哈希的。您可以了解“ hashable”的含义in the docs。不过，您可以使用词典列表：

"Indicators": [
    {'Name': ..., 'Value': ...},
    {'Name': ..., 'Value': ...},
    ...
]

Answer 2

您缺少列表：

            'Indicators': [
                {"Name": "sales",
                 "Value": ca_ttc_n,
                 "Unit": currency,
                 "Rank": rank},
                  ...
              ]
            }

Answer 3

这是因为您试图设置没有任何键值的字典指标（具有字典等不可散列的值）。

response = {'Date': input_date,
                'Comparable date': date_comparable,
                'Indicators': {
                    'key1':{"Name": "sales",
                     "Value": ca_ttc_n,
                     "Unit": currency,
                     "Rank": rank},
                    'key2':{"Name": "sales_progression",
                     "Value": progression_percentage,
                     "Unit": percentage,
                     "Rank": rank},
                    'key3':{"Name": "customer_items_number",
                     "Value": nb_art_pass_caiss,
                     "Unit": "Units",
                     "Rank": rank},
                    'key4':{"Name": "customer_items_number_progression",
                     "Value": nb_art_pass_caiss_prog,
                     "Unit": percentage,
                     "Rank": rank},
                    'key5':{"Name": "basket",
                     "Value": panier,
                     "Unit": currency,
                     "Rank": rank}
                }
}

否则，如果不需要按键，请在指示器中列出一个列表。

API提供TypeError：不可哈希类型：'dict'

3 个答案: