Question

我正在尝试合并多行并按制表符将其分开：

audited 41915 packages in 5.767s
found 596 vulnerabilities (1 low, 2 moderate, 593 high)
  run `npm audit fix` to fix them, or `npm audit` for details

但我收到此错误：

TypeError：序列项0：预期的str实例，找到了列表。

输入：

with open('combined.txt', "r") as f:
    print(' '.join(line.strip("\n").split("\t") for line in f))

所需的输出：

azubi
arch=pc
mhz#2666
os=linux
ipv6net=auto

adrian
arch=pc
memory#4096
os=solaris11
osdist=opensolaris

Answer 1

假设您的数据用换行符分隔，则可以使用此代码段读取和格式化数据。

    $soapClient = new SoapClient($this->wsdl,
                                    array('location' => $this->EndPointURL."AdaptivePayments/Preapproval/", 
                                          'uri' => "urn:Preapproval",
                                          'soap_version' => SOAP_1_1, 
                                          'trace' => 1, //debugging option

    'compression' => SOAP_COMPRESSION_ACCEPT,

    'stream_context' => $ctx)); //adding the stream context option containing the http headers

    $response = objectToArray($soapClient->Preapproval($params));

    } catch (SoapFault $e) { 
        $response = objectToArray($e);
    }

    return $response;

}

这给出了输出：

    var row = '<tr>';
        row += '<td><input type="text" class="form-control" name="name" id="name"></td>';
        row += '<td>';
        row += '<select>';
        row += '<option value="volvo"> Volvo</option>';
        row += '<option value="saab">Saab</option>';
        row += '<option value="mercedes">Mercedes</option>';
        row += '<option value="audi">Audi</option>';
        row += '</select>';
        row += '</td>';
        row += '<td><input type="text" class="form-control" name="phone" id="phone"></td>';
        row += '<td>' + actions + '</td>';
        row += '</tr>';

Answer 2

检查括号的位置，我想应该是

with open(file, "r") as f:
    print(' '.join(line.strip("\n").split("\t")) for line in f)

但是，(' '.join(line.strip("\n").split("\t")) for line in f)将返回generator，print()然后在generator上打印信息，例如<generator object <genexpr> at 0x0000020B62EE1A20>。我想那不是你想要的。您可以改用：

with open(file, "r") as f:
    for line in f:
        print(' '.join(line.strip("\n").split("\t")))

编辑：两行获取所需输出的快速修复：

with open(file, "r") as f:
    print(' '.join([line.strip() if line != '\n' else line for line in f]).replace('\n ', '\n'))

但是，如果您必须定期加载多个此类文件，我还是很hacky，我建议编写一个适当的文件解析器。

Answer 3

因此，尽管我认为其他答案已经解决了错误，但它们并没有为您提供预期的输出。

我假设与示例输入一样，在输出中形成1行的文本始终由单个空白行分隔。

我有两种可能的解决方案：

方法1 ：

with open('test.txt', 'r') as in_f:
    content=in_f.read()


content2 = content.splitlines()
new_lines = []
while content2:
    try:
        split_idx = content2.index('')
        new_lines.append(content2[0:split_idx])
        content2 = content2[split_idx+1:]
    except ValueError as e:
        new_lines.append(content2)
        content2 = False

for line in new_lines:
    print(' '.join(line))

azubi arch=pc mhz#2666 os=linux ipv6net=auto
adrian arch=pc memory#4096 os=solaris11 osdist=opensolaris

方法2 ：

with open('test.txt', 'r') as in_f:
    content=in_f.read()

content2 = content.splitlines()

size = len(content2) 
idx_list = [idx + 1 for idx, val in enumerate(content2) if val == '']

res = [content2[i: j] for i, j 
    in zip([0] + idx_list, idx_list + 
    ([size] if idx_list[-1] != size else []))] 

for line in res:
    print(' '.join(line).strip())

azubi arch=pc mhz#2666 os=linux ipv6net=auto
adrian arch=pc memory#4096 os=solaris11 osdist=opensolaris

如何使用python 3拆分列表？

3 个答案: