我使用一个Cloud Function调整图像大小,然后使用第二个功能将新的图像URL上传到Cloud Firestore。
但是有些东西行不通,因为第二个函数永远不会运行。 我需要uid和postId,可以在其中更新网址。
如何调用第二个函数来更新Firestore中的img网址?
代码
const { functions, tmpdir, dirname, join, sharp, fse, gcs } = require('../../admin');
const runtimeOpts = {
timeoutSeconds: 120,
memory: '1GB',
};
exports.resizeImages = functions
.runWith(runtimeOpts)
.storage.object()
.onFinalize(async (object, context) => {
const bucket = gcs.bucket(object.bucket);
const filePath = object.name;
const fileName = filePath.split('/').pop();
const bucketDir = dirname(filePath);
const workingDir = join(tmpdir(), 'resize');
const tmpFilePath = join(workingDir, 'source.png');
if (fileName.includes('@s_') || !object.contentType.includes('image')) {
return false;
}
await fse.ensureDir(workingDir);
await bucket.file(filePath).download({ destination: tmpFilePath });
// creates 3 new images with these sizes..
const sizes = [1920, 720, 100];
var newUrl = null;
const uploadPromises = sizes.map(async size => {
const ext = fileName.split('.').pop();
const imgName = fileName.replace(`.${ext}`, '');
const newImgName = `${imgName}@s_${size}.${ext}`;
var imgPath = join(workingDir, newImgName);
newUrl = imgPath;
await sharp(tmpFilePath)
.resize({ width: size })
.toFile(imgPath);
return bucket.upload(imgPath, {
destination: join(bucketDir, newImgName),
});
});
await Promise.all(uploadPromises);
//second function
functions.firestore.document('users/{uid}/posts/{id}').onCreate(async (snap, context) => {
console.log(context.params);
const uid = context.params.uid;
const userPost = functions.firestore.doc('users/{uid}/posts}');
userPost.update({
url: newUrl,
});
});
return fse.remove(workingDir);
});
答案 0 :(得分:1)
您的第二个功能似乎嵌入在第一个功能中。这行不通。所有功能定义都必须在顶层,以便Firebase CLI可以检测到它们并分别进行部署。
如果您实际上不需要两个单独的函数定义,则只需在一个函数中执行所有工作即可,不要尝试使用函数SDK来完成任何工作。 Functions SDK仅用于定义要部署的功能。