我有以下数据表
import pandas as pd
dt = pd.DataFrame({'id_audience': ['Female 13-17', 'Female 18-20'],
'gender': ['female', 'female'],
'age_min': [13, 18],
'age_max': [17, 20]})
我想扩展此数据框,以增加一列(age
),并且age
应该在age_min
和age_max
之间。
最终结果如下:
dt = pd.DataFrame({'id_audience': ['Female 13-17', 'Female 13-17', 'Female 13-17', 'Female 13-17',
'Female 13-17', 'Female 18-20', 'Female 18-20', 'Female 18-20', ],
'gender': ['female', 'female', 'female', 'female', 'female', 'female', 'female', 'female'],
'age_min': [13, 13, 13, 13, 18, 18, 18, 18],
'age_max': [17, 17, 17, 17, 20, 20, 20, 20],
'age': [13, 14, 15, 16, 17, 18, 19, 20]})
有什么想法吗?
答案 0 :(得分:4)
也可以像{Wen一样使用explode
,但在“最小/最大年龄”列上可以直接访问范围
dt.assign(
age=[np.arange(x, y+1) for x, y in zip(dt['age_min'], dt['age_max'])]
).explode('age').reset_index(drop=True)
id_audience gender age_min age_max age
0 Female 13-17 female 13 17 13
1 Female 13-17 female 13 17 14
2 Female 13-17 female 13 17 15
3 Female 13-17 female 13 17 16
4 Female 13-17 female 13 17 17
5 Female 18-20 female 18 20 18
6 Female 18-20 female 18 20 19
7 Female 18-20 female 18 20 20
答案 1 :(得分:3)
这是使用新熊猫0.25.0 explode
s=dt['id_audience'].str.extractall('(\d+)')
dt['age']= [list(range(y.iloc[0,0],y.iloc[1,0]+1)) for x , y in s.astype(int).groupby(level=0)]
dt=dt.explode('age').reset_index(drop=True)
答案 2 :(得分:2)
使用Index.repeat
和GroupBy.cumcount
作为age
列的计数器:
dt = dt.loc[dt.index.repeat(dt['age_max'] - dt['age_min'] + 1)]
dt['age'] = dt['age_min'] + dt.groupby(level=0).cumcount()
dt = dt.reset_index(drop=True)
print (dt)
id_audience gender age_min age_max age
0 Female 13-17 female 13 17 13
1 Female 13-17 female 13 17 14
2 Female 13-17 female 13 17 15
3 Female 13-17 female 13 17 16
4 Female 13-17 female 13 17 17
5 Female 18-20 female 18 20 18
6 Female 18-20 female 18 20 19
7 Female 18-20 female 18 20 20