我尝试通过PHP
拖放进行一些重新排序,并通过this tutorial进行一些ajax
进行重新排序。
我为我的需要设置了文件,但没有任何反应。
在我的index.php
上更改与我的MySQL
$sql = "SELECT * FROM channels ORDER BY channel_number";
$users = $mysqli->query($sql);
while($user = $users->fetch_assoc()){
?>
<tr id="<?php echo $user['id'] ?>">
<td><?php echo $user['channel_number'] ?></td>
<td><?php echo $user['title'] ?></td>
</tr>
<?php } ?>
这是index.php
中的Java脚本:
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jqueryui/1.12.1/jquery-ui.min.js"></script>
</head>
<body>
<script type="text/javascript">
$( ".row_position" ).sortable({
delay: 150,
stop: function() {
var selectedData = new Array();
$('.row_position>tr').each(function() {
selectedData.push($(this).attr("id"));
});
updateOrder(selectedData);
}
});
function updateOrder(data) {
$.ajax({
url:"ajaxPro.php",
type:'post',
data:{position:data},
success:function(){
alert('your change successfully saved');
}
})
}
</script>
</html>
这是我要更改的ajaxPro.php
:
require('db_config.php');
$position = $_POST['position'];
$i=1;
foreach($position as $k=>$v){
$sql = "Update `channels` SET `channel_number`=".$i." WHERE `id`=".$v;
$mysqli->query($sql);
$i++;
}
当我尝试重新排序时,只想更改字段channel_number,但什么都没发生。我的错误在哪里
答案 0 :(得分:0)
我已经更改了一些代码,并打开了一些日志,但是仍然有问题。如果任何人都可以协助将会很高兴。在这里:
index.php
<div class="container">
<h3 class="text-center">Dynamic Drag and Drop table rows in PHP Mysql - ItSolutionStuff.com</h3>
<table id="myTable" class="table table-bordered">
<thead>
<tr>
<th scope="col">ID</th>
<th scope="col">#</th>
<th scope="col">Name</th>
</tr>
</thead>
<tbody class="row_position">
<?php
require('db_config.php');
$sql = "SELECT * FROM channels ORDER BY channel_number";
$users = $mysqli->query($sql);
while($user = $users->fetch_assoc()){
?>
<tr id="<?php echo $user['id'] ?>"> <!-- data-channel-number="<?php echo $user['channel_number'] ?>">-->
<td><?php echo $user['id'] ?></td>
<td class="index"><?php echo $user['channel_number'] ?></td>
<td><?php echo $user['title'] ?></td>
</tr>
<?php } ?>
</tbody>
</table>
</div> <!-- container / end -->
</body>
<!--<script type="text/javascript">
$( ".row_position" ).sortable({
delay: 150,
stop: function() {
//console.log(chArray);
}
});
</script>-->
<script>
var fixHelperModified = function(e, tr) {
var $originals = tr.children();
var $helper = tr.clone();
$helper.children().each(function(index) {
$(this).width($originals.eq(index).width())
});
return $helper;
},
updateIndex = function(e, ui) {
$('td.index', ui.item.parent()).each(function (i) {
$(this).text(i+1);
});
};
$("#myTable tbody").sortable({
distance: 5,
//delay: 100,
opacity: 0.6,
cursor: 'move',
helper: fixHelperModified,
update: function() {
var chArray = [];
$('.row_position>tr').each(function() {
chArray.push({
chid : $(this).attr("id"),
chnumber : $(this).closest('tr').find('td.index').text()
});
});
console.log(chArray);
// console.log(data);
$.ajax({
url:"ajaxPro.php",
type:'post',
data:{position:chArray},
success:function(data){
console.log(data);
//alert('your change successfully saved');
},
error: function (error) {
// console.log(error);
}
})
},
stop: updateIndex
}).disableSelection();
</script>
</html>
ajaxPro.php
error_reporting(1);
require('db_config.php');
$data = $_POST['position'];
echo $data;
//$i=1;
foreach($data as $d){
echo $d['chnumber'];
$sql = "Update channels SET channel_number=".$d['chnumber']." WHERE id=".$d['chid'];
$mysqli->query($sql);
}
在浏览器中看起来一切都已更改(如果我将chanel从位置4移到位置2,它将在屏幕上更改为位置2,但是数组chnumber
中的位置仍然是4,我不知道如何改变这个。
这是一些照片。 1st order when you load page