我有这个测试用例，在没有任何类的情况下，它可以在ES5中完美运行：
Player1Drugs = new ObservableCollection<DrugInventoryItem>(World.Player1.DrugInventory);
如何在TypeScript中编写此代码？
在函数定义中添加let Foo = function() { this.bar = 'baz'; };
let foo = new Foo();
之后，但仍然出现错误。
this所以我尝试将函数强制转换为可更新的类型，但随后提示
let Foo = function(this: { bar: string }) { this.bar = 'baz'; };
let foo = new Foo();
// ^^^^^^^^^
// 'new' expression, whose target lacks a construct signature, implicitly has an 'any' type.
接口语法也无济于事：
let Foo = function(this: { bar: string }) { this.bar = 'baz'; } as new() => { bar: string; };
// ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
// Conversion of type '(this: { bar: string; }) => void' to type 'new () => { bar: string; }' may be a mistake because neither type sufficiently overlaps with the other. If this was intentional, convert the expression to 'unknown' first.
// Type '(this: { bar: string; }) => void' provides no match for the signature 'new (): { bar: string; }'.
let foo = new Foo();
因此，似乎唯一的出路是先将函数强制转换为未知函数，然后再转换为可更新的类型。
let Foo = function(this: { bar: string }) { this.bar = 'baz'; } as { new(): { bar: string; } };
// ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
// Conversion of type '(this: { bar: string; }) => void' to type 'new () => { bar: string; }' may be a mistake because neither type sufficiently overlaps with the other. If this was intentional, convert the expression to 'unknown' first.
// Type '(this: { bar: string; }) => void' provides no match for the signature 'new (): { bar: string; }'.
let foo = new Foo();
在没有引入类开销的情况下，真的没有更简单的方法可以在TypeScript中键入此函数吗？