Question

我是iPhone SDK的新手。现在我正在使用CALayers进行编程，我非常喜欢它 - 不像UIViews那么昂贵，而且代码比OpenGL ES sprites少得多。

我有这个问题：是否有可能在CALayer上获得触摸事件？我了解如何使用

在UIView上获取触摸事件

-(void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event

但我无法找到关于如何在CALayer对象上获取触摸事件的任何地方，例如，漂浮在3D空间中的橙色方块。我拒绝相信我是唯一一个对此感到好奇的人。

我感谢任何帮助！

Answer 1

好的 - 回答了我自己的问题！假设您在视图控制器的主图层中有一堆CALayers，并且您希望它们在触摸它们时变为不透明度0.5。在视图控制器类的.m文件中实现此代码：

-(void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    if ([touches count] == 1) {
        for (UITouch *touch in touches) {
            CGPoint point = [touch locationInView:[touch view]];
            point = [[touch view] convertPoint:point toView:nil];

            CALayer *layer = [(CALayer *)self.view.layer.presentationLayer hitTest:point];

            layer = layer.modelLayer;
            layer.opacity = 0.5;
        }
    }
}

Answer 2

与第一个答案类似。

- (CALayer *)layerForTouch:(UITouch *)touch {
    UIView *view = self.view;

    CGPoint location = [touch locationInView:view];
    location = [view convertPoint:location toView:nil];

    CALayer *hitPresentationLayer = [view.layer.presentationLayer hitTest:location];
    if (hitPresentationLayer) {
        return hitPresentationLayer.modelLayer;
    }

    return nil;
} 

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    UITouch *touch = [touches anyObject];
    CALayer *hitLayer = [self layerForTouch:touch];

    // do layer processing...
}

Answer 3

我发现我的坐标错误

point = [[touch view] convertPoint:point toView:nil];

我不得不将其改为

point = [[touch view] convertPoint:point toView:self.view];

获取正确的图层

Answer 4

Egor T answer已针对Swift 4更新：

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?)
{
    super.touchesBegan(touches, with: event)

    if let touch = touches.first, let touchedLayer = self.layerFor(touch)
    {
        //Here you will have the layer as "touchedLayer"
    }
}

private func layerFor(_ touch: UITouch) -> CALayer?
{
    let view = self.view
    let touchLocation = touch.location(in: view)
    let locationInView = view.convert(touchLocation, to: nil)

    let hitPresentationLayer = view.layer.presentation()?.hitTest(locationInView)
    return hitPresentationLayer?.model()
}

如何在CALayer上获得触摸事件？

4 个答案: