我正试图重新定义keras的binary_crossentropy损失函数,以便我可以对其进行自定义,但是它给我的结果与现有结果不同。
我在Keras 2.2.4上使用TF 1.13.1。
我经历了Keras的github代码。我的理解是model.compile(optimizer ='adam',loss ='binary_crossentropy',metrics = ['accuracy'])中的损失是使用tensorflow_backend.py中定义的binary_crossentropy定义在loss.py中。 >
我运行了一个虚拟数据并进行了模型测试。这是我的发现:
from numpy.random import seed
seed(1)
from tensorflow import set_random_seed
set_random_seed(2)
import tensorflow as tf
from keras import losses
import keras.backend as K
import keras.backend.tensorflow_backend as tfb
from keras.layers import Dense
from keras import Sequential
#Dummy check of loss output
def binary_crossentropy_custom(y_true, y_pred):
return K.mean(binary_crossentropy_custom_tf(y_true, y_pred), axis=-1)
def binary_crossentropy_custom_tf(target, output, from_logits=False):
"""Binary crossentropy between an output tensor and a target tensor.
# Arguments
target: A tensor with the same shape as `output`.
output: A tensor.
from_logits: Whether `output` is expected to be a logits tensor.
By default, we consider that `output`
encodes a probability distribution.
# Returns
A tensor.
"""
# Note: tf.nn.sigmoid_cross_entropy_with_logits
# expects logits, Keras expects probabilities.
if not from_logits:
# transform back to logits
_epsilon = tfb._to_tensor(tfb.epsilon(), output.dtype.base_dtype)
output = tf.clip_by_value(output, _epsilon, 1 - _epsilon)
output = tf.log(output / (1 - output))
return tf.nn.sigmoid_cross_entropy_with_logits(labels=target,
logits=output)
logits = tf.constant([[-3., -2.11, -1.22],
[-0.33, 0.55, 1.44],
[2.33, 3.22, 4.11]])
labels = tf.constant([[1., 1., 1.],
[1., 1., 0.],
[0., 0., 0.]])
custom_sigmoid_cross_entropy_with_logits = binary_crossentropy_custom(labels, logits)
keras_binary_crossentropy = losses.binary_crossentropy(y_true=labels, y_pred=logits)
with tf.Session() as sess:
print('CUSTOM sigmoid_cross_entropy_with_logits: ', sess.run(custom_sigmoid_cross_entropy_with_logits), '\n')
print('KERAS keras_binary_crossentropy: ', sess.run(keras_binary_crossentropy), '\n')
#CUSTOM sigmoid_cross_entropy_with_logits: [16.118095 10.886106 15.942386]
#KERAS keras_binary_crossentropy: [16.118095 10.886106 15.942386]
#Dummy check of model accuracy
X_train = tf.random.uniform((3, 5), minval=0, maxval=1, dtype=tf.dtypes.float32)
labels = tf.constant([[1., 0., 0.],
[0., 0., 1.],
[1., 0., 0.]])
model = Sequential()
#First Hidden Layer
model.add(Dense(5, activation='relu', kernel_initializer='random_normal', input_dim=5))
#Output Layer
model.add(Dense(3, activation='sigmoid', kernel_initializer='random_normal'))
#I ran model.fit for each model.compile below 10 times using the same X_train and provide the range of accuracy measurement
# model.compile(optimizer='adam', loss='binary_crossentropy', metrics =['accuracy']) #0.748 < acc < 0.779
# model.compile(optimizer='adam', loss=losses.binary_crossentropy, metrics =['accuracy']) #0.761 < acc < 0.778
model.compile(optimizer='adam', loss=binary_crossentropy_custom, metrics =['accuracy']) #0.617 < acc < 0.663
history = model.fit(X_train, labels, steps_per_epoch=100, epochs=1)
我希望自定义损失函数能够提供相似的模型精度输出,但事实并非如此。任何想法?谢谢!
答案 0 :(得分:1)
Keras会根据损失自动选择要使用的accuracy
实现,如果您使用自定义损失,此方法将无效。但是在这种情况下,您可以明确使用正确的精度,即binary_accuracy
:
model.compile(optimizer='adam', loss=binary_crossentropy_custom, metrics =['binary_accuracy'])