iOS13：如何检测状态栏的单击事件？

Question

在我的appDelegate中，我覆盖touchesBegan来检测何时单击状态栏：

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    [super touchesBegan:touches withEvent:event];

    CGPoint location = [[[event allTouches] anyObject] locationInView:kWindow];
    CGRect statusBarFrame = [UIApplication sharedApplication].statusBarFrame;

    if (CGRectContainsPoint(statusBarFrame, location)) {
        ///do something 
    }
}

在iOS 13之前，此功能有效；在iOS 13上则没有。该方法从不执行。我该如何解决？

Answer 1

经过研究，我发现状态栏不再是iOS13上应用程序的一部分，而是系统UI（“跳板”）的一部分。您需要通过UIStatusBarManager

进行访问

所以这不再起作用：

from collections import deque
class Solution:

    def solve(self, A, B, C, D, board):
        # @param A, B: (x, y) co-ordinates of start position
        # @param C, D: (x, y) co-ordinates of target position
        # @param board : list of strings
        # @return minimum moves required or impossible

        seen = set()

        def neighbors(i, j):
            @param i, j: co-ordinates of current position
            @return list with all possible valid moves

            nei = []
            x, y = i - 1, j
            while x >= 0 and board[x][y] != '1':
                nei.append((x, y))
                x -= 1

            x, y = i + 1, j
            while x < len(board) and board[x][y] != '1':
                nei.append((x, y))
                x += 1

            x, y = i, j - 1
            while y >= 0 and board[x][y] != '1':
                nei.append((x, y))
                y -= 1

            x, y = i, j + 1
            while y < len(board[0]) and board[x][y] != '1':
                nei.append((x, y))
                y += 1

            return nei

        def bfs(i, j):
            que = deque([(i, j, 0)])

            while que:
                m, n, level = que.popleft()
                seen.add((m, n))

                if m == C and n == D:
                    return level

                for x, y in neighbors(m, n):
                    if (x, y) not in seen:
                        que.append((x, y, level + 1))
                        seen.add((x, y))

            return -1

        return bfs(A, B)

在iOS 13中，您需要像下面这样获取StatusBar框架：

CGRect statusBarFrame = [UIApplication sharedApplication].statusBarFrame;

Answer 2

在iOS 13中，StatusBar事件由UIStatusBarManager管理，当单击StatusBar时将调用以下方法：

-[UIStatusBarManager _handleScrollToTopAtXPosition:]
-[UIStatusBarManager handleTapAction:]

因此，您可以钩住-[UIStatusBarManager handleTapAction:]来检测StatusBar点击事件