我有一个Json类“ GetAllDevices()”。我的JSON响应包含一个对象数组/列表,其中每个对象都具有以下公共属性。
public class GetAllDevices
{
[JsonProperty("_id")]
public string Id { get; set; }
[JsonProperty("name")]
public string Name { get; set; }
[JsonProperty("type")]
public string Type { get; set; }
[JsonProperty("actions")]
public Action[] Actions { get; set; }
public class Action
{
public string _id { get; set; }
public Action_Def action_def { get; set; }
}
public class Action_Def
{
public string _id { get; set; }
public string name { get; set; }
}
}
我想基于其“类型”创建2个包含上述所有属性的通用列表。 lstfoo1列表包含所有属性(_id,名称类型和操作),其中type =“ foo1”。同样,lstfoo2是一个List,其中包含上述属性,类型为=“ foo2”。
到目前为止我所做的:
string strJson=getJSON();
Foo1 lstfoo1=new Foo1();
Foo2 lstfoo2=new Foo2();
List<Foo1> foo1list= lstfoo1.GetDeviceData(strJson);
List<Foo2> foo2list = lstfoo2.GetDeviceData(strJson);
public class AllFoo1: GetAllDevices
{
}
public class AllFoo2: GetAllDevices
{
}
public abstract class HomeDevices<T>
{
public string type { get; set; }
public string _id { get; set; }
public List<AllFoo1> lstfoo1{ get; set; }
public List<AllFoo2> lstfoo2{ get; set; }
public abstract List<T> GetDeviceData(string jsonResult);
}
public class Foo1: HomeDevices<AllFoo1>
{
public Foo1()
{
type = "foo1";
}
public override List<AllFoo1> GetDeviceData(string jsonResult)
{
var lst =Newtonsoft.Json.JsonConvert.DeserializeObject<List<AllFoo1>>(jsonResult);
var lst1 = lst.Where(x => x.Type.Equals(type)).ToList();
return lst1;
}
}
public class Foo2: HomeDevices<AllFoo2>
{
public Foo2()
{
type = "foo2";
}
public override List<AllFoo2> GetDeviceData(string jsonResult)
{
var lst = Newtonsoft.Json.JsonConvert.DeserializeObject<List<AllFoo2>>(jsonResult);
var lst1 = lst.Where(x => x.Type.Equals(type)).ToList();
return lst1;
}
}
我的问题是,有没有更简单的方法使用抽象类来做到这一点?我可以直接将我的“ GetAllDevices”类转换为抽象类并继承并反序列化并创建通用列表吗?
答案 0 :(得分:2)
如果我正确理解了您的问题,这应该会有所帮助。让我知道您是否有疑问,或者如果您有任何疑问,请联系我们。我很快就将它们组合在一起,无需进行测试。
可以改进Type属性的定义方式,但我还是保留了它。
public class MyApplication
{
public void DoWork()
{
string json = getJSON();
DeviceTypeOne foo1 = new DeviceTypeOne();
DeviceTypeTwo foo2 = new DeviceTypeTwo();
IList<DeviceTypeOne> foo1Results = foo1.GetDeviceData(json); // calls GetDeviceData extension method
IList<DeviceTypeTwo> foo2Results = foo2.GetDeviceData(json); // calls GetDeviceData extension method
}
}
// implemented GetDeviceData as extension method of DeviceBase, instead of the abstract method within DeviceBase,
// it's slightly cleaner than the abstract method
public static class DeviceExtensions
{
public static IList<T> GetDeviceData<T>(this T device, string jsonResult) where T : DeviceBase
{
IEnumerable<T> deviceDataList = JsonConvert.DeserializeObject<IEnumerable<T>>(jsonResult);
IEnumerable<T> resultList = deviceDataList.Where(x => x.Type.Equals(typeof(T).Name));
return resultList.ToList();
}
}
// abstract base class only used to house common properties and control Type assignment
public abstract class DeviceBase : IDeviceData
{
protected DeviceBase(string type)
{
if(string.IsNullOrEmpty(type)) { throw new ArgumentNullException(nameof(type));}
Type = type; // type's value can only be set by classes that inherit and must be set at construction time
}
[JsonProperty("_id")]
public string Id { get; set; }
[JsonProperty("name")]
public string Name { get; set; }
[JsonProperty("type")]
public string Type { get; private set;}
[JsonProperty("actions")]
public DeviceAction[] Actions { get; set; }
}
public class DeviceTypeOne : DeviceBase
{
public DeviceTypeOne() : base(nameof(DeviceTypeOne))
{
}
}
public class DeviceTypeTwo : DeviceBase
{
public DeviceTypeTwo() : base(nameof(DeviceTypeTwo))
{
}
}
// implemented GetAllDevices class as IDeviceData interface
public interface IDeviceData
{
string Id { get; set; }
string Name { get; set; }
string Type { get; }
DeviceAction[] Actions { get; set; }
}
// renamed and relocated class Action to DeviceAction
public class DeviceAction
{
public string Id { get; set; }
public DeviceActionDefinition DeviceActionDefinition { get; set; }
}
// renamed and relocated Action_Def to DeviceActionDefinition
public class DeviceActionDefinition
{
public string Id { get; set; }
public string Name { get; set; }
}
答案 1 :(得分:1)
将方法GetDeviceData()
的实现转移到基类应该足够简单。
为此,您需要在T
上添加一个约束,以便编译器对基本类型有更多的了解。您还需要实现一个构造函数,以填充您在其中使用的具体类型的type
字符串。这是确保在该方法中将其用于比较时始终填充该值的必要措施:
public abstract class HomeDevices<T> where T: GetAllDevices
{
public HomeDevices(string concreteType)
{
type = concreteType;
}
public string type { get; set; }
public string _id { get; set; }
public List<AllFoo1> lstfoo1 { get; set; }
public List<AllFoo2> lstfoo2 { get; set; }
//This method is now generic and works for both.
public List<T> GetDeviceData(string jsonResult)
{
var lst = Newtonsoft.Json.JsonConvert.DeserializeObject<List<T>>(jsonResult);
var lst1 = lst.Where(x => x.Type.Equals(type)).ToList();
return lst1;
}
}
我希望有帮助。