Question

我的情况是，我尝试使用UITableview和custom cell创建sections。在这里，我也尝试一次checkmark进行one cell选择。如果用户单击该部分，则该部分下的所有相关行都应像组选择一样显示复选标记。它无法正常工作。另外，在这种情况下搜索主要复合体之一。提供一些解决办法。

下面我正在使用的代码，

import UIKit

class CustomCell: UITableViewCell {
    @IBOutlet weak var myCellLabel: UILabel!

    override func setSelected(_ selected: Bool, animated: Bool) { // Check Mark Selection Not Properly Working
        super.setSelected(selected, animated: animated)
        self.accessoryType = selected ? .checkmark : .none
    }
}

class ViewController: UIViewController,UISearchControllerDelegate, UISearchResultsUpdating, UISearchBarDelegate, UITableViewDelegate, UITableViewDataSource  {

    // These strings will be the data for the table view cells
    let sectionNames = ["pizza", "deep dish pizza", "calzone"]
    let data = [["Margarita", "BBQ Chicken", "Pepperoni"],
                ["sausage", "meat lovers", "veggie lovers"],
                ["sausage", "chicken pesto", "prawns", "mushrooms"]]

   //var filteredData: [[String]]!
    let cellReuseIdentifier = "cell"
    var searchController : UISearchController!
    @IBOutlet var tableView: UITableView!

    override func viewDidLoad() {
        super.viewDidLoad()

        //filteredData = data
        self.tableView.rowHeight = 78.5
    }


    @IBAction func searchAction(_ sender: Any) {

        // Create the search controller and specify that it should present its results in this same view
        searchController = UISearchController(searchResultsController: nil)

        // Set any properties (in this case, don't hide the nav bar and don't show the emoji keyboard option)
        searchController.hidesNavigationBarDuringPresentation = false
        searchController.searchBar.keyboardType = UIKeyboardType.asciiCapable
        searchController.dimsBackgroundDuringPresentation = false
        searchController.searchBar.barTintColor = #colorLiteral(red: 0.3118804693, green: 0.435135603, blue: 0.9917090535, alpha: 1)
        searchController.searchBar.backgroundColor = #colorLiteral(red: 1.0, green: 1.0, blue: 1.0, alpha: 1.0)

        // Make this class the delegate and present the search
        self.searchController.searchBar.delegate = self
        searchController.searchResultsUpdater = self
        present(searchController, animated: true, completion: nil)
    }


    // MARk: - Tableview Delegates
    func numberOfSections(in tableView: UITableView) -> Int {
        return data.count
    }

    func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return data[section].count
    }

    func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
        let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! CustomCell
        cell.myCellLabel.text = data[indexPath.section][indexPath.row]
        return cell
    }

    func tableView(_ tableView: UITableView, titleForHeaderInSection section: Int) -> String? {
        return sectionNames[section]
    }

    func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
        let selectedValue = data[indexPath.section][indexPath.row]
        //send selectedValue to server...
    }

    func updateSearchResults(for searchController: UISearchController) { // SEARCH NOT WORKING

        if let searchText = searchController.searchBar.text {
            filteredData = searchText.isEmpty ? data : data.filter({(dataString: String) -> Bool in
                return dataString.range(of: searchText, options: .caseInsensitive) != nil
            })
            tableView.reloadData()
        }
    }
}

Answer 1

尝试一下-

将此行添加到其注释掉的地方。

var filteredData: [[String]] = data

然后将您的UITableViewDatasource方法更改为使用filteredData而不是data。例如

func numberOfSections(in tableView: UITableView) -> Int {
    return filteredData.count
}

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    return filteredData[section].count
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! CustomCell
    cell.myCellLabel.text = filteredData[indexPath.section][indexPath.row]
    return cell
}

data仅应在搜索委托函数中使用。

Answer 2

我建议您在模型中采用这些结构

file cells1.tif

这些结构将在单元格中同时包含节名称和选择。在您的班级中，您的模型就像这样：

struct MyData {
    var value: String?
    var selected: Bool = false
}
struct tableData{
    var sectionName: String
    var data: [MyData]
}

由于您正在重复使用同一表视图进行搜索，因此必须检查使用了哪些数据源，如果搜索栏处于活动状态但尚无输入，则不要重新加载数据

class ViewController: UIViewController, UITableViewDelegate, UITableViewDataSource, UISearchControllerDelegate, UISearchResultsUpdating, UISearchBarDelegate {

    var searchController : UISearchController!
    var rowNames = [tableData]()

    var filteredData: [tableData]!
    let cellReuseIdentifier = "cell"
    @IBOutlet var tableView: UITableView!


    override func viewDidLoad() {
        super.viewDidLoad()
        //filteredData = rowNames
    }


    //MARK: List Tableview
    func numberOfSections(in tableView: UITableView) -> Int {
        return rowNames.count
    }

     func tableView(_ tableView: UITableView, titleForHeaderInSection section: Int) -> String? {
    return rowNames[section].sectionName
}

PD：这里缺少一件事，当在标题上敲击时如何选择所有行，但是这是您应该提出的另一个问题。

Swift UITableview单元格复选标记和搜索不起作用

2 个答案: