如何设置事实女巫在Ansible角色的所有主机上可见

时间:2019-08-01 11:23:03

标签: ansible

我将角色设置为事实

- name: Check if manager already configured
  shell: >
    docker info | perl -ne 'print "$1" if /Swarm: (\w+)/'
  register: swarm_status

- name: Init cluster
  shell: >-
    docker swarm init
    --advertise-addr "{{ ansible_default_ipv4.address }}"
  when: "'active' not in swarm_status.stdout_lines"

- name: Get worker token
  shell: docker swarm join-token -q worker
  register: worker_token_result

- set_fact:
    worker_token: "{{ worker_token_result.stdout  }}"

然后,我要访问其他主机上的worker_token。这是我的主要剧本,事实是在swarm-master角色中定义的

- hosts: swarm_cluster
  become: yes
  roles:
    - docker

- hosts: swarm_cluster:&manager
  become: yes
  roles:
    - swarm-master

- hosts: swarm_cluster:&node
  become: yes
  tasks:
    - debug:
        msg: "{{ worker_token }}"

我正在获取未定义的变量。如何使其在全球范围内可见? 当然,如果我在同一主机上运行调试,它会完美地工作。

1 个答案:

答案 0 :(得分:2)

如果您的目标只是从另一台主机上访问worker_token,则可以使用hostvars变量,并在定义变量的组中进行如下迭代:

- hosts: swarm_cluster:&node
  tasks:
  - debug:
      msg: "{{ hostvars[item]['worker_token'] }}"
    with_items: "{{ groups['manager'] }}"

如果您的目标是全局定义变量,则可以添加步骤以在所有主机上定义变量,如下所示:

- hosts: all
  tasks:
  - set_fact:
      worker_token_global: "{{ hostvars[item]['worker_token'] }}"
    with_items: "{{ groups['manager'] }}"

- hosts: swarm_cluster:&node
  tasks:
  - debug:
      var: worker_token_global