Question

我一直在使用cakephp paginations选项2天。我需要创建一个INNER联接列出几个字段，但我必须处理搜索以过滤结果。这是我通过$this->passedArgs

处理搜索选项的代码的一部分

function crediti() {

    if(isset($this->passedArgs['Search.cognome'])) {
                debug($this->passedArgs);

                $this->paginate['conditions'][]['Member.cognome LIKE'] = str_replace('*','%',$this->passedArgs['Search.cognome']);

        }
        if(isset($this->passedArgs['Search.nome'])) {
                $this->paginate['conditions'][]['Member.nome LIKE'] = str_replace('*','%',$this->passedArgs['Search.nome']);

        }

之后

$this->paginate = array(

            'joins' => array(array('table'=> 'reservations',
            'type' => 'INNER',
            'alias' => 'Reservation',
            'conditions' => array('Reservation.member_id = Member.id','Member.totcrediti > 0' ))),
            'limit' => 10);
        $this->Member->recursive = -1;
        $this->paginate['conditions'][]['Reservation.pagamento_verificato'] = 'SI';
        $this->paginate['fields'] = array('DISTINCT Member.id','Member.nome','Member.cognome','Member.totcrediti');
        $members = $this->paginate('Member');
        $this->set(compact('members'));

INNER JOIN效果很好，但$ this-＆gt; paginations会忽略每个$this->paginate['conditions'][] by $this->passedArgs，我无法知道如何解决这个问题。调试中没有查询，只有原始INNER JOIN。有人可以帮助我吗？非常感谢你

更新：没有运气。我已经处理了这部分代码很长时间了。如果我使用

if(isset($this->passedArgs['Search.cognome'])) {
                    $this->paginate['conditions'][]['Member.cognome LIKE'] = str_replace('*','%',$this->passedArgs['Search.cognome']);

            }
$this->paginate['conditions'][]['Member.sospeso'] = 'SI';
        $this->Member->recursive = 0;
        $this->paginate['fields'] = array(
            'Member.id','Member.nome','Member.cognome','Member.codice_fiscale','Member.sesso','Member.region_id',
            'Member.district_id','Member.city_id','Member.date','Member.sospeso','Region.name','District.name','City.name');
        $sospesi = $this->paginate('Member');

一切顺利，从调试我收到$this->paginate['conditions'][]['Member.cognome LIKE']的第一个条件和条件，如您所见数组$this->passedArgs

Array
(
    [Search.cognome] => aiello
)

Array $this->paginate['conditions'][]
(
    [0] => Array
        (
            [Member.cognome LIKE] => aiello
        )

    [1] => Array
        (
            [Member.sospeso] => NO
        )

但是，如果我使用paginate编写联接，$this->paginate['conditions'][]将忽略所有内容，并从调试中获取，只需$this->paginate['conditions'][]['Reservation.pagamento_verificato'] = 'SI'; 另一点信息。如果我把所有处理$this->paginate['conditions'][]['Reservation.pagamento_verificato'] = 'SI';的东西都放了在$this->paginate JOIN之前，$this->paginate['conditions'][]中没有任何内容。

Answer 1

这是一个老问题，所以我只会回顾一下如何在Google的分页中加入JOIN，就像我一样从谷歌来到这里。这是来自Widget控制器的示例代码，将Widget.user_id FK加入User.id列，仅显示当前用户（在条件中）：

// Limit widgets shown to only those owned by the user.
$this->paginate = array(
    'conditions' => array('User.id' => $this->Auth->user('id')),
    'joins' => array(
        array(
            'alias' => 'User',
            'table' => 'users',
            'type' => 'INNER',
            'conditions' => '`User`.`id` = `Widget`.`user_id`'
        )
    ),
    'limit' => 20,
    'order' => array(
        'created' => 'desc'
    )
);
$this->set( 'widgets', $this->paginate( $this->Widget ) );

这使查询类似于：

SELECT widgets.* FROM widgets 
INNER JOIN users ON widgets.user_id = users.id 
WHERE users.id = {current user id}

仍然是分页。

Answer 2

我不确定你是否需要那些[] - 试着这样做：

$this->paginate['conditions']['Reservation.pagamento_verificato'] = 'SI';

Answer 3

我在调用paginate方法时使用条件。

$this->paginate($conditions)

这对我有用，我希望它适合你！

如果您已设置上一个参数，则可以使用：

$this->paginate(null,$conditions)

Answer 4

这可能对某人有帮助.... 这就是我在cakephp中使用分页进行复杂连接的方法。

$parsedConditions['`Assessment`.`showme`'] = 1;
$parsedConditions['`Assessment`.`recruiter_id`'] = $user_id;

$this->paginate = array(
'conditions' => array($parsedConditions ),
  'joins' => array(
    array(
        'alias' => 'UserTest',
        'table' => 'user_tests',
        'type' => 'LEFT',
        'conditions' => '`UserTest`.`user_id` = `Assessment`.`testuser_id`'
    ),
    array(
        'alias' => 'RecruiterUser',
        'table' => 'users',
        'type' => 'LEFT',
        'conditions' => '`Assessment`.`recruiter_id` = `RecruiterUser`.`id`'
    )
    ,
    array(
        'alias' => 'OwnerUser',
        'table' => 'users',
        'type' => 'LEFT',
        'conditions' => '`Assessment`.`owner_id` = `OwnerUser`.`id`'
    )
),
  'fields' => array('Assessment.id', 'Assessment.recruiter_id', 'Assessment.owner_id', 'Assessment.master_id', 'Assessment.title', 'Assessment.status', 'Assessment.setuptype','Assessment.linkkey', 'Assessment.review', 'Assessment.testuser_email', 'Assessment.counttype_2', 'Assessment.bookedtime', 'Assessment.textqstatus', 'Assessment.overallperc', 'UserTest.user_id', 'UserTest.fname', 'UserTest.lname', 'RecruiterUser.company_name', 'OwnerUser.company_name'),
  'limit' => $limit,
        'order'=>   array('Assessment.endtime' => 'desc')   
    );

Cakephp $ this-＆gt;带有自定义JOIN和过滤选项的分页

4 个答案: