Question

我有一个表列，其日期与我公司中的发送订单相对应。格式如下：2019-07-31 09:52:09.427。

ModDate

2019-07-31 09:48:08.810    
2019-07-31 09:48:09.000    
2019-07-31 09:48:09.070    
2019-07-31 09:48:08.070    
2019-07-31 09:48:45.083    
2016-09-09 13:13:30.680    
2016-09-09 13:15:00.907    
2016-09-09 13:27:45.647    
2016-09-09 13:32:15.217    
2016-09-09 14:32:15.917    
2016-09-09 14:32:15.917

我想拥有一个SQL表，该表计算在特定日期发送的订单数量，例如：

Date            Number of sent orders
2019-07-31      23

Answer 1

将count和cast datetime用作date

 select cast ( ModDate as date) as d ,count(*) from t
group by cast ( ModDate as date)

Answer 2

您可以尝试执行此操作，这将为您提供每个不同日期的计数结果。

  select distinct cast(ModDate as date) as Date, count(ModDate) as [Count] from table group by cast(ModDate as date)

Answer 3

您可以使用此查询

SELECT CONVERT(DATE,CreatedDate) as [DateTime], COUNT(*) as [Count]
FROM Orders
GROUP BY CONVERT(DATE,CreatedDate)

Answer 4

您可以尝试以下方法：

select moddate ,count(*) over (partition by cast (ModDate as date)) from yourtable

同一日期发生了多少次

4 个答案: