Question

我想根据JSON API中的状态动态更改框颜色。例如，已批准= Colors.green，已拒绝= Colors.red，已提交= Colors.blue。

this is the image of my current app 我强调状态

如何实现？

这是我获取API的方式：

Future getCalendar() async{
  List<Events> list;

    String api = "http://200.0.0.104/api/dynamic/uspGetCalendarEvents_mobile?EmployeeId=5";
    var res = await http.get(Uri.encodeFull(api), headers: {"Accept": "application/json"});

        var data = json.decode(res.body);
        var rest = data["data"] as List;
        list = rest.map<Events>((json) => Events.fromJson(json)).toList();

    return list;
  }

这就是我循环数据的方式：

getCalendar().then((data){

          for (var a =0; a <  data.length; a++ )
          {
             _events.addAll({DateTime.parse(data[a].start.toString().replaceAll("-", "")) :  data[a].title.toString().split(",")  });
          }
    });

这是我的小部件：

 Widget _buildEventList() {
    return ListView(
      children: _selectedEvents
          .map((event) => Container(
                decoration: BoxDecoration(
                  color: Colors.blue, // i want to change the color
                  border: Border.all(width: 0.8),
                  borderRadius: BorderRadius.circular(12.0),
                ),
                margin: const EdgeInsets.symmetric(horizontal: 8.0, vertical: 4.0),
                child: ListTile(
                  title: Text(event.toString()),
                  onTap: () => print('$event tapped!'),
                ),
              ))
          .toList(),
    );
  }

Answer 1

您可以创建一种根据条件（假设event.toString（）= Rejected，Approved或Submitted）返回Color的方法：


Color _getColorByEvent(String event) {
  if (event == "Approved") return Colors.green;
  if (event == "Rejected") return Colors.red;
  return Colors.blue;
}

...

BoxDecoration(
                color: _getColorByEvent(event.toString()), // i want to change the color
                border: Border.all(width: 0.8),
                borderRadius: BorderRadius.circular(12.0),
              ),

Answer 2

例如颜色调用方法

 return ListView(
children: _selectedEvents
    .map((event) => Container(
          decoration: BoxDecoration(
            color: Colors.blue, // i want to change the color
            border: Border.all(width: 0.8),
            borderRadius: BorderRadius.circular(12.0),
          ),
          margin: const EdgeInsets.symmetric(horizontal: 8.0, vertical: 4.0),
          child: ListTile(
            title: Text(event.toString()),
            onTap: () => print('$event tapped!'),
          ),
        ))
    .toList(),
  );

}

Color _getColor(Map event){ swith(event) { return value } }

Answer 3

像这样创建一个映射键值对。

  Map<String, Color> colorCode ={"Approved":Colors.green,"Rejected":Colors.red};
eg:- 
    final color=colorCode["Approved"];

然后传递密钥来映射，您将获得对应的密钥的值。

Answer 4

这就是我的做法...

Color getColorForStatus(OrderStatus event) {
      switch (event) {
        case OrderStatus.PLACED:
          return Colors.black;
          break;
        case OrderStatus.ORDER_CONFIRMED:
          return Colors.lightBlue;
          break;
        case OrderStatus.OUT_FOR_DELIVERY:
          return new Color(0xFFE5AC0E);
          break;
        case OrderStatus.DELIVERED:
          return Colors.green;
          break;
        case OrderStatus.PAYMENT_DECLINED:
          return new Color(0xFFFFA401);
          break;
        case OrderStatus.CANCELED:
          return Colors.red;
          break;
        default:
          return Colors.black;
          break;
      }
    }

颤抖如何根据JSON API中的状态更改颜色

4 个答案: