学校给了我一个XML文档,我必须在屏幕上显示信息。据我所知,Xml反序列化将是最简单/最好的解决方案。
到目前为止,我有这个:
public static List<Project> ProjectListDeserialize(string path)
{
XmlSerializer serializer = new XmlSerializer(typeof(List<Project>));
Stream filestream = new FileStream(path, FileMode.Open);
return (List<Project>)serializer.Deserialize(filestream);
}
public static Projects ProjectsDeserialize(string path)
{
XmlSerializer serializer = new XmlSerializer(typeof(Projects));
Stream filestream = new FileStream(path, FileMode.Open);
return (Projects)serializer.Deserialize(filestream);
}
这就是XML文档的样子:
<?xml version="1.0" encoding="utf-16" ?>
<Projects xmlns="http://www.pulse.nl/DynamicsAX/2009/DataSets" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<Project ID ="1000.0001" CustomerID="1000">
<Name>Project data key performance indicators</Name>
<Status>WorkInProgress</Status>
<StartDate>2011-01-01</StartDate>
<ExpectedCompletionDate>2011-08-01</ExpectedCompletionDate>
<CompletionDate xsi:nil="true" />
</Project>
<Project ID ="1000.0008" CustomerID="1000" ParentID="1000.0001">
<Name>Implementation</Name>
<Status>WaitListed</Status>
<StartDate>2011-06-01</StartDate>
<ExpectedCompletionDate>2011-08-01</ExpectedCompletionDate>
<CompletionDate xsi:nil="true" />
</Project>
</Projects>
两种方法都抛出相同的异常:
<Projects xmlns='http://www.pulse.nl/DynamicsAX/2009/DataSets was not expected
如何正确反序列化上面的xml?任何样品都会有所帮助!
答案 0 :(得分:2)
问题很可能是您未将正确的命名空间指定为Project
类的属性。
您可以告诉XmlSerializer在反序列化期间忽略名称空间(检查this answer)。
或者,您可以使用XmlTypeAttribute
:
[XmlType(Namespace = "http://www.pulse.nl/DynamicsAX/2009/DataSets")]
public class Project
{
...
}
答案 1 :(得分:1)
尝试在default namespace的构造函数中为XML文档指定XmlSerializer:
var serializer = new XmlSerializer(typeof(Projects), "http://www.pulse.nl/DynamicsAX/2009/DataSets");
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