Question

//JavaScript:

    function concatArrays() {
      var recentlyCompleted = ["rc1", "rc2"];
      var upcomingActivities = [];
      var decisionsRequired = [];
      var records = [];
        switch(true) {
          case (recentlyCompleted.length >0):
            records.concat(recentlyCompleted);
            console.log("recentlyCompleted.length >0");
            console.log(records);
          case (upcomingActivities.length >0):
            records.concat(upcomingActivities);
            console.log("upcomingActivities.length >0");
            console.log(records);
          case (decisionsRequired.length >0):
            records.concat(decisionsRequired);
            console.log("decisionsRequired.length >0");
            console.log(records);
            break;
        }
      document.getElementById("demo").innerHTML = JSON.stringify(records);
      
      var records2 = recentlyCompleted.concat(upcomingActivities).concat(decisionsRequired);
      document.getElementById("demo2").innerHTML = JSON.stringify(records2);
    }

    <head>
      <meta charset="utf-8">
      <meta name="viewport" content="width=device-width">
      <title>switch(true)</title>
    </head>
    <body>
      <p>Click the button to join arrays.</p>
      <button onclick="concatArrays()">Try it</button>
      <p id="demo"></p>
      <p id="demo2"></p>
    </body>

对不起，我已经读过，如果不是序列，则主要优势是可以忽略break语句并执行多个块。我想在我的case（true）代码中执行多个块。但是我发现这个简单的代码有问题。

非常抱歉，您能否使用switch（true）解释部分代码的问题？谢谢！

执行一个以上的块：

执行正确答案的屏幕截图：

function concatArrays() {
  var recentlyCompleted = ["rc1", "rc2"];
  var upcomingActivities = [];
  var decisionsRequired = [];
  var records = [];
  switch (true) {
    case (recentlyCompleted.length > 0):
      records = records.concat(recentlyCompleted);
      console.log("recentlyCompleted.length >0");
      console.log(records);
    case (upcomingActivities.length > 0):
      records = records.concat(upcomingActivities);
      console.log("upcomingActivities.length >0");
      console.log(records);
    case (decisionsRequired.length > 0):
      records = records.concat(decisionsRequired);
      console.log("decisionsRequired.length >0");
      console.log(records);
      break;
  }
  document.getElementById("demo").innerHTML =
    JSON.stringify(records);

  var records2 = recentlyCompleted
    .concat(upcomingActivities)
    .concat(decisionsRequired);
  document.getElementById("demo2").innerHTML =
    JSON.stringify(records2);
}

Answer 1

没有case的{{1}}不会重新评估下一个break的相等性，而只是无条件地运行称为fallthrough的块。我怀疑这就是您想要的。改为使用多个连续的case语句（而不是if链）-如果您不关心日志语句，则可以采用if-else方法。

第二，records2创建一个新数组，它不会通过追加目标来对其进行突变。有关各种解决方案，请参见How to append something to an array?或How to extend an existing JavaScript array with another array, without creating a new array。

Answer 2

您应该看一下价差运算符：

var records = [...recentlyCompleted, ...upcomingActivities, ..decisionsRequired]

您的records和records2总是一样。

为什么我的带有switch（true）和Array.concat（）的代码无法正常工作

2 个答案: