Question

由于语法错误或与系统调用结合使用awk的不正确，我快疯了。我已经阅读了几页有关它的内容，但是仍然无法正常工作。查看我的代码。

当前错误是：

awk: cmd. line:1: /sent/ { system("echo \"mail has been sent\"")} !/sent/ { system("curl -k -i -u username:password -X POST -H "Content-Type: application/json" -d '{"source": "client-01", "name": "smtp-bounce-check", "output": "Cannot send e-mail, e-mail bounced", "status": 2}' https://monitoring:4567/results")}
awk: cmd. line:1:                                                                                                                                                    ^ syntax error

我尝试使用单引号，双引号进行转义，但仍然无法正常工作。

#!/bin/bash

gen_data1='{"source": "client-1", "name": "smtp-bounce-check", "output": "Cannot send e-mail, e-mail bounced", "status": 2}'

tail -f /var/log/maillog| grep --line-buffered "relay=some-host.name.com"|grep --line-buffered "status="| awk '/sent/ { system("echo \"mail has been sent\"")} !/sent/ { system("curl -k -i -u username:password -X POST -H "Content-Type: application/json" -d '"'${gen_data1}'"' https://monitoring:4567/results")}'

Answer 1

您需要进一步逃脱。

gen_data1='{"source": "client-1", "name": "smtp-bounce-check", "output": "Cannot send e-mail, e-mail bounced", "status": 2}';
gen_data1_escaped=$(<<<"$gen_data1" sed 's/"/\\\\\\"/g')
awk '
   /sent/{ 
       system("echo \"mail has been sent\"")
   }
   !/sent/{ 
       system("curl -k -i -u username:password -X POST -H \"Content-Type: application/json\" -d \"'"${gen_data1_escaped}"'\" https://monitoring:4567/results")
   }
'

您需要对"中的所有gen_data1进行两次转义。就是将每个"转换为\\\"。它将首先由awk进行转义，然后由system()调用中的shell进行转义。
"Content-Type: application/json"周围的引号也必须转义
${gen_data1}周围的引号必须存在且必须为双引号。根据我的发现，在system()内的awk内不能使用单引号，即。测试awk "{ system('echo hello world') }"

尝试在awk中使用系统调用时出现语法错误

1 个答案: