Laravel的with方法返回null

Question

laravel雄辩的with（）方法，$ this-> model :: find（$ no）->持有人可以看到结果。但是方法总是为空

  public function holder()
    {
        return $this->belongsTo('App\Entities\Holder', 'holder_no', 'no');
    }


public function bankAccount()
    {
        return $this->hasMany('App\Entities\BankAccount', 'holder_no', 'no');
    }



public function getBankCardDetail(array $params): array
{
    $card_detail = $this->model::with('holder:no,name')
        ->select([
            'holder_no'
        ])
        ->where([
            'no'=>$params['no']
        ])
        ->first()
        ->toArray();

    return $card_detail;
}


   "data": {
        "holder_no": "XXXXXXXXXX",
        "holder": null
    }


select `holder_no` from `bank_accounts` where (`no` = 'CGRWVF93HAOYHXZSCR4KVZ') limit 1  
select `no`, `name` from `holders` where `holders`.`no` in (0) 

我不知道问题出在哪里。 laravel 5.8

Answer 1

no和名称应以不起作用的方式选择。