Question

如何在json中找到并比较值？让我们说

{"data 1": {
    "product": "54",
    "info": {
        "browser": "Safari",
        "isp": "isp sample",
        "width": 500,
        "ip": 109.24.55.121,
        "uid": 124,
        "location": 10.23,123.90
    }
}
{"data 2": {
    "campaign": "2",
    "info": {
        "browser": "Mozilla",
        "isp": "isp sample",
        "width": 500,
        "ip": 109.24.55.121,
        "uid": 231,
        "location": 10.23,123.90
    }
}
{"data 3": {
    "campaign": "2",
    "info": {
        "browser": "Mozilla",
        "isp": "isp sample",
        "width": 500,
        "ip": 109.24.55.121,
        "uid": 227,
        "location": 10.23,123.90
    }
}
{"same data": {
    "campaign": "2",
    "info": {
        "browser": "Mozilla",
        "isp": "isp sample",
        "width": 500,
        "ip": 109.24.55.121,
        "uid": 227,
        "location": 10.23,123.90
    }
}
{"same data": {
    "campaign": "2",
    "info": {
        "browser": "Mozilla",
        "isp": "isp sample",
        "width": 500,
        "ip": 109.24.55.121,
        "uid": 227,
        "location": 10.23,123.90
    }
}

我想输出有什么相似之处。什么字符串和什么值。

Answer 1

$data = json_decode($your_json_data);

foreach($data as $datum) {
    .... do some processing ...
}

json_encode / json_decode将在本机PHP数组和本机Javascript数组/对象之间进行转换。您没有说要处理哪种语言，但由于JSON IS javascript，因此无法在javascript端进行解码。只是加载数据然后去。在PHP上，您首先需要将其解码为本机PHP数组。

JSON比较元素或元素的存在

1 个答案: