我试图在检测到轮廓后裁剪图像,然后使用python,opencv和numpy从图像中提取信息。
检测轮廓成功,但是后来我找不到裁剪的方法。我尝试了一些代码,但没有得到想要的结果:
true
数组import numpy as np
import cv2
image = cv2.imread('2.jpg') # Read in your image
blurred=cv2.blur(image,(23,51))#blur the image
gray=cv2.cvtColor(blurred,cv2.COLOR_BGR2GRAY)#gray scale
ret,threshold=cv2.threshold(gray , 2 , 255 , cv2.THRESH_BINARY+cv2.THRESH_OTSU)
contours,hierachy=cv2.findContours(threshold,cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE)#detect contours
mask = np.zeros_like(image) # Create mask where white is what we want, black otherwise
cv2.drawContours(mask, contours, 0, (0 ,0,255),1)
out = np.zeros_like(image) # Extract out the object and place into output image
out[mask == 255] = image[mask == 255]
# Now crop
mask=mask.transpose(2,0,1).reshape(-1,mask.shape[1])
(x, y) = np.where(mask == 255)
(topx, topy) = (np.min(x), np.min(y))
(bottomx, bottomy) = (np.max(x), np.max(y))
topx=topx
topy=topy
bottomx=bottomx
bottomy=bottomy
out = out[topx:bottomx,topy:bottomy]
print(out)
为空,这很奇怪,因为当我打印out
,topx
,topy
和bottomx
时,我得到了整数,因此从逻辑上讲裁剪会给我结果。
答案 0 :(得分:0)
通常,如果检测到轮廓,则可以通过在代码中 var target_ss = "your-spreadsheet-id";
var ss_sheets = SpreadsheetApp.openById(target_ss).getSheets();
for (var i = 0; i < ss_sheets.length; i++){
Logger.log(ss_sheets[i].getDataRange().setWrap(true));
}
之后添加以下几行来裁剪轮廓:
contours, hierarchy = cv2.findContours(threshold, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
答案 1 :(得分:0)
您可以尝试以下方法:
x, y = [], []
for contour_line in contours:
for contour in contour_line:
x.append(contour[0][0])
y.append(contour[0][1])
x1, x2, y1, y2 = min(x), max(x), min(y), max(y)
cropped = img[y1:y2, x1:x2]
来源:https://stackoverflow.com/questions/41069831/opencv-python-crop-image-using-numpy-array?rq=1#=