Question

尝试在many2many字段中插入值时出现错误，您可以查看完整日志here

这是字段的声明

initial_project_ids = fields.Many2many(string="Initial project", comodel_name="project.project",
                                       compute="_get_initial_project", relation="init", column1="in", column2="it",
                                       store=True)

这是写方法的主要内容

@api.multi
def write(self, vals):
    res = super(Project, self).write(vals)
    if vals.get('upstream_project_ids') and self._context.get('update', True):
        for upstream_project in self.upstream_project_ids:
            upstream_project.with_context(update=False).update({'downstream_project_id': self.id})
        # new implementation
        # no risk of recursion
        if self.project_type == "internal":
            super(Project, self).write(
                {'members_ids': [(6, 0, self.mapped("upstream_project_ids").mapped("members_ids").ids)],
                 'managers_ids': [(6, 0, self.mapped("upstream_project_ids").mapped("managers_ids").ids)],
                 'partners': [(6, 0, self.mapped("upstream_project_ids").mapped("partners").ids)]})
        if self.project_type == 'valorization' and not self.check_protection:
            super(Project, self).write(
                {'managers_ids': [(6, 0, self.mapped("upstream_project_ids").mapped("managers_ids").ids)],
                 'partners': [(6, 0, self.mapped("upstream_project_ids").mapped("partners").ids)]})
    if vals.get('downstream_project_id') and self._context.get('update', True):
        self.downstream_project_id.with_contex(update=False).update({'upstream_project_ids': (4, self.id)})
    return res

这是导致错误的方法

@api.depends("upstream_project_ids")
def _get_initial_project(self):
    for record in self:
        e = record.mapped("upstream_project_ids")
        bak_e = False
        while e:
            bak_e = e
            if record in e:
                raise exceptions.Warning(
                    _(
                        'Recursion found')
                )
            e = e.mapped("upstream_project_ids")
        if bak_e:
            record.update(
                {'initial_project_ids': [(6, 0, bak_e.ids)]})

我不知道这是怎么回事，这是什么问题，我尝试使用write方法，情感（=）但它不起作用。当我将initial_project_ids字段声明为many2one时，它起作用了。

Odoo 12：在many2many字段中错误INSERT INTO init（in，it）

0 个答案: