无法使用硒定位元素列表

时间:2019-07-29 06:40:10

标签: python selenium web-scraping

我需要抓取一些页面。我想要的零件的确切结构如下:

<div class="someclasses">
<h3>...</h3> # Not needed
<ul class="ul-class1 ul-class2">
<li id="li1-id" class="li-class1 li-class2">
<div id ="div1-id" class="div-class1 div-class2 ... div-class6">
<div class="div2-class">
    <div class="div3-class">...</div> #Not needed
    <div class="div4-class1 div4-class2 div4-class3">
        <a href="href1" data-control-id="id1" data-control-name="name" id ="a1-id" class="a-class1 a-class2">
            <h3 class="h3-class1 h3-class2 h3-class3">Text1</h3>
        </a></div>
    <div>...</div> # Not needed
</div>
</li>
<li id="li2-id" class="li-class1 li-class2">
<div id ="div2-id" class="div-class1 div-class2 ... div-class6">
<div class="div2-class">
    <div class="div3-class">...</div> #Not needed
    <div class="div4-class1 div4-class2 div4-class3">
        <a href="href2" data-control-id="id2" data-control-name="name" id ="a2-id" class="a-class1 a-class2">
            <h3 class="h3-class1 h3-class2 h3-class3">Text2</h3>
        </a></div>
    <div>...</div> # Not needed
</div>
</li>
# More <li> elements
</ul>
</div>

现在我想要的是同时获得Textshrefs。在上面的示例中,我使用的命名是完全现实的,也就是说,真实网页中的名称也相同。我当前使用的代码是:

elems = driver.find_elements_by_xpath("//div[@class='someclasses']/ul[@class='ul-class1']/li[@class='li-class1']")
print(len(elems))
for elem in elems:
    elem1 = driver.find_element_by_xpath("./a[@data-control-name='name']")
    names2.append(elem1.text)
    print(elem1.text)
    hrefs.append(elem.get_attribute("href"))

上面print语句的结果为0,因此基本上找不到元素。谁能告诉我我在做什么错。

1 个答案:

答案 0 :(得分:0)

您只使用了部分类名...在XPATH中,您需要完整的类名...

仅供参考:使用CSS,您可以使用部分类名...

如果要使用XPATH,请尝试:

elems = driver.find_elements_by_xpath("//div[@class='someclasses']//li//a")
print(len(elems))
for elem in elems:
    elem1 = driver.find_element_by_xpath("./a[@data-control-name='name']")
    names2.append(elem1.text)
    print(elem1.text)
    new_href = elem.get_attribute("href")
    print(new_href)
    hrefs.append(new_href)