如何为Python代码编写Scala代码

Question

我试图将Python代码实现为等效的Scla代码，但混淆了特定的代码段。代码是

public class FileOpener extends AsyncTask<String, Void, Uri> {

    private ThreadLocal<Context> context;
    private String type;

    public FileOpener(Context context, ProgressBar loading) {
        this.context = new ThreadLocal<>();
        this.context.set(context);
    }

    @Override
    protected Uri doInBackground(String[] data) {
        //At index 0 are stored the bytes, index 1 is stored the name 
        //and index 2 is stored the type
        type = data[2];
        java.io.File file = new File(context.get().getFilesDir(), data[1]);
        byte[] bytes = FileManager.convertBytesToFile(data[0]);

        FileManager.writeToFile(context.get(), bytes, data[1]);
    }

    @Override
    protected void onPostExecute(Uri uri) {

    }
}

关于代码的更多详细信息是here