Question

我正在尝试将某些内容保存到.py文件中，当我保存它时，它会使该文件夹出现，但不转储其中的任何内容，我也不知道为什么！因此，我收到EOFError的错误：尝试加载数据时出现输入不足的情况。

def save():

        ult = [player.name, player.account_balance, player.cash, player.hunger, player.job, player.skill, player.inventory, player.pin, player.fulltime_days_worked]

        Save = input("Do you want to save? (y/n): ").lower().strip()
        print("="*15)
        if Save == "y":
            with open("Savegame.py", "wb") as f:
                pickle.dump(str(ult), f)
                quit = input("Your session has been saved! Do you want to quit(y/n)").lower()
                print("="*15)
                if quit == "y":
                    shutdown.terminate()
                elif quit == "n":
                    main_menu()
                print("="*15)



    def load():

        save1 = input("Do you want to load last session?(y/n): ").lower()
        print("="*15)
        if save1 == "y":
            with open("Savegame.py", "rb") as f:
                ult = pickle.load(f)
                main_menu()
        elif save1 == "n":
            main_menu()

我希望数据也存储在我也尝试过.txt的.py文件中

更新

这对我有用！由于某种原因，除非我加载它并给出EOFError，否则它不会保存数据，然后它会保存数据。所以这是我的解决方法。我提供了在代码的开头加载数据的选项，它的工作原理就像一个魅力！

def Save_game():
    try:
        ult = [player.name, player.account_balance, player.cash, player.hunger, player.job, player.skill, player.inventory, player.pin, player.fulltime_days_worked]

        save = input("do you want to save?(y/n) ").lower()
        if save == "y":
            with open('Savegame.py', 'wb') as file:
                pickle.dump(ult, file)
                with open('Savegame.py', 'rb') as file:
                    ult = pickle.load(file)

    except EOFError:
        print("You saved the game!")
        quit = input("Do you want to quit? (y/n): ")
        if quit == "y":
            shutdown.terminate()
        elif quit == "n":
            main_menu()

不能用泡菜存储数据

0 个答案: