Question

背景

我有以下示例df

import pandas as pd
Names =    [list(['Jon', 'Smith', 'jon', 'John']),
           list(['Mark', 'Marky', 'marcs']),
           list(['Bob', 'bobby', 'Bobs'])]
df = pd.DataFrame({'Text' : ['Jon J Smith is Here and jon John from ', 
                                   'When he came Mark was Marky but not marcs so', 
                                   'I like Bob and bobby and also Bobs diner '], 

                      'P_ID': [1,2,3], 
                      'P_Name' : Names

                     })

#rearrange columns
df = df[['Text', 'P_ID', 'P_Name']]
df


    Text                                       P_ID  P_Name
0   Jon J Smith is Here and jon John from       1   [Jon, Smith, jon, John]
1   When he came Mark was Marky but not marcs   2   [Mark, Marky, marcs]
2   I like Bob and bobby and also Bobs diner    3   [Bob, bobby, Bobs]

此df与此处Alter text in pandas column based on names看到的“旧问题”有所不同。我的新df和“新问题”的唯一区别是P_Name列中名称的格式，如下所示：

 #old names from old question
 array(['Smith, Jon J', 'Rider, Mary', 'Doe, Jane Ann', 'Tucker, Tom'], dtype=object) 
 #new names from new question
 array([list(['Jon', 'Smith', 'jon', 'John']),
        list(['Mark', 'Marky', 'marcs']), list(['Bob', 'bobby', 'Bobs'])], dtype=object)

目标

在Text列中，将**PHI**添加到与[Jon, Smith, jon, John]中找到的值相对应的值（例如P_Name）

问题

在Alter text in pandas column based on names的“旧问题”中使用解决方案时

 df['Text'].replace(df['P_Name'].str.split(', *').apply(lambda l: ' '.join(l[::-1])),'**PHI**',regex=True)

我收到以下错误：

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-79-895f7ea46849> in <module>()
----> 1 df['Text'].replace(df['P_Name'].str.split(', *').apply(lambda l: ' '.join(l[::-1])),'**PHI**',regex=True)



/usr/local/Cellar/python3/3.6.1/Frameworks/Python.framework/Versions/3.6/lib/python3.6/site-packages/pandas/core/series.py in apply(self, func, convert_dtype, args, **kwds)
   2353             else:
   2354                 values = self.asobject
-> 2355                 mapped = lib.map_infer(values, f, convert=convert_dtype)
   2356 
   2357         if len(mapped) and isinstance(mapped[0], Series):

pandas/_libs/src/inference.pyx in pandas._libs.lib.map_infer (pandas/_libs/lib.c:66645)()

<ipython-input-79-895f7ea46849> in <lambda>(l)
----> 1 df['Text'].replace(df['P_Name'].str.split(', *').apply(lambda l: ' '.join(l[::-1])),'**PHI**',regex=True)

TypeError: 'float' object is not subscriptable

所需结果

我想要以下内容，类似于“旧问题” Alter text in pandas column based on names

中的答案

               Text                                       P_ID  P_Name
0   **PHI** J **PHI** is Here and **PHI** **PHI** from       1   [Jon, Smith, jon, John]
1   When he came **PHI** was **PHI** but not **PHI**         2   [Mark, Marky, marcs]
2   I like **PHI** and **PHI** and also **PHI** diner        3   [Bob, bobby, Bobs]

问题

考虑到我的P_Name列现在包含列表列表，我如何实现预期的结果？

Answer 1

IIUC，您需要series.replace，它将列表作为arg：

to_replace：str，regex，list，dict，Series，int，float或None

df=df.assign(Text=df.Text.replace(df.P_Name,'**PHI**',regex=True))

根据名称列表更改“熊猫”列中的文本

1 个答案: