我有一个循环。在每一轮中,我需要将问题数据添加到MongoDB数据库中。这很好。但是,我想在循环进入下一轮之前获得新插入的 Question 的 _id 。这是我有问题的地方。服务器返回 _id 并在该时间之前进入下一轮,需要一定的时间。因此,我需要一种方法来等待服务器响应,并且只有在该响应移至下一轮循环之后。
这是我的后端代码:
router.post("/createQuestion", (req, res) => {
const newQuestion = new Question({
description: req.body.description,
type: req.body.type,
model: req.body.model
});
newQuestion.save().then(question => res.json(question._id))
.catch(err => console.log(err));
});
这是我的axios函数,它在一个单独的文件中,并导入到类中:
export const createQuestion = (questionData) => dispatch => {
axios.post("/api/scorecard/createQuestion", questionData)
.then(res => {
return res.data;
}).catch(err =>
console.log("Error adding a question")
);
};
这是我班上的代码:
JSON.parse(localStorage.getItem(i)).map(question => {
const newQuestion = {
description: question.description,
type: question.questionType,
model: this.props.model
}
const question_id = this.props.createQuestion(newQuestion);
console.log(question_id);
}
控制台显示 undefined 。
答案 0 :(得分:0)
我遇到了同样的问题,我通过将数组问题发送到节点并逐个读取问题并使用下一个Question ID更新来解决了同样的问题。
router.post("/createQuestion", (req, res) => {
let d =[questionarray];
let i = 0;
let length = d.length;
var result = [];
try {
const timeoutPromise = (timeout) => new Promise((resolve) => setTimeout(resolve, timeout));
for (i = 0; i < length; i++) {
await timeoutPromise(1000); // 1000 = 1 second
let CAT_ID = parseInt(d[i].CAT_ID);
let TOPIC_ID = parseInt(d[i].TOPIC_ID);
let Q_DESC = (d[i].Q_DESC);
let OPT_1 = (d[i].OPT_1);
let OPT_2 = (d[i].OPT_2);
let OPT_3 = (d[i].OPT_3);
let OPT_4 = (d[i].OPT_4);
let ANS_ID = (d[i].ANS_ID);
let TAGS = (d[i].TAGS);
let HINT = (d[i].HINT);
let LEVEL = d[i].LEVEL;
let SRNO = d[i].SrNo;
let qid;
const savemyData = async (data) => {
return await data.save()
}
var myResult = await Question.find({ TOPIC_ID: TOPIC_ID }).countDocuments(function (err, count) {
if (err) {
console.log(err);
}
else {
if (count === 0) {
qid = TOPIC_ID + '' + 10001;
const newQuestion = new Question({
Q_ID: qid,
CAT_ID: CAT_ID,
TOPIC_ID: TOPIC_ID,
Q_ID: qid,
Q_DESC: Q_DESC,
OPT_1: OPT_1,
OPT_2: OPT_2,
OPT_3: OPT_3,
OPT_4: OPT_4,
ANS_ID: ANS_ID,
HINT: HINT,
TAGS: TAGS,
LEVEL: LEVEL,
Q_IMAGE: ''
})
await savemyData(newQuestion)
.then(result => { return true })
.catch(err => { return false });
//`${SRNO} is added successfully`
//`${SRNO} is Failed`
}
else if (count > 0) {
// console.log(count)
Question.find({ TOPIC_ID: TOPIC_ID }).sort({ Q_ID: -1 }).limit(1)
.then(question => {
qid = question[0].Q_ID + 1;
const newQuestion = new Question({
Q_ID: qid,
CAT_ID: CAT_ID,
TOPIC_ID: TOPIC_ID,
Q_ID: qid,
Q_DESC: Q_DESC,
OPT_1: OPT_1,
OPT_2: OPT_2,
OPT_3: OPT_3,
OPT_4: OPT_4,
ANS_ID: ANS_ID,
HINT: HINT,
TAGS: TAGS,
LEVEL: LEVEL,
Q_IMAGE: ''
})
await savemyData(newQuestion)
.then(result => { return true })
.catch(err => { return false });
})
.catch(err => console.log(err));
}
}
});
if (myResult)
result.push(`${SRNO} is added successfully`);
else
result.push(`${SRNO} is Failed`);
}
// console.log(result)
return res.json(result);
}
catch (err) {
//res.status(404).json({ success: false })
console.log(err)
}
});
答案 1 :(得分:0)
首先,您的函数createQuestion
不返回值,因此分配给question_id始终是不确定的。无论如何,由于您的createQuestion
函数中有一个调度,所以我假设您使用redux
,所以我建议您使用redux-thnk
,将获取新的动作逻辑拆分为重动作,并使用redux
状态中的问题ID值,而不是返回createQuestion
中的值。您可以在课堂上听questionID
的更改,如果发生更改,请分派下一个问题的保存。