我有以下代码,评论应该清楚解释。我想查询文件以获取给定的信息,然后在返回结果后,在结果数组中添加一个字段。然后,在我的程序中稍后访问生成的数组。
以下代码的问题是,我认为数组是第二次尝试循环时的最后一条记录...并且重置($ stmt1)失败,因为$ stmt1“不是数组对象”...
<?php
$sql1 = "SELECT dpdpt, SUM(dpbir) FROM dwhlib.dwdptstr WHERE dpdpt < '312' GROUP BY dpdpt ";
//Setup connection
$conn_resource = db2_connect ( "*LOCAL", "", "" );
//Verify connection successful
if (! $conn_resource) {
echo "Connection failed. SQL Err:";
echo db2_conn_error ();
echo "<br/>";
echo db2_conn_errormsg ();
exit ();
}
//Prepare the stmt
$stmt1 = db2_prepare ( $conn_resource, $sql1 );
//Execute the prepared statement
if (! db2_execute ( $stmt1 )) {
echo 'The db2 execute failed. ';
echo 'SQLSTATE value: ' . db2_stmt_error ();
echo ' Message: ' . db2_stmt_errormsg ();
exit ();
}
//Loop through all rows, adding a third field
while ( $row1 = &db2_fetch_array ( $stmt1 ) ) {
$row1[2] = "TEST";
}
//Reset stmt or array back to first record
//??
//Print results
echo "<table border=1>";
while ( $row = db2_fetch_array ( $stmt1 ) ) {
echo "<tr>";
echo " <td>" . $row[0] . "</td>";
echo " <td>" . $row[1] . "</td>";
echo " <td>" . $row[2] . "</td>";
echo "</tr>";
}
echo "</table>";
?>
答案 0 :(得分:2)
我认为这不可行。但无论如何,尝试这样做并不是一个令人信服的理由。
保持简单。只是第一次构建一个数组。
$rows = array();
//Loop through all rows, adding a third field
while ( $row = db2_fetch_array ( $stmt1 ) ) {
$row[2] = "TEST";
$rows[] = $row;
}
db2_free_result($stmt1);
//Print results
echo "<table border=1>";
foreach($rows as $row) {
echo "<tr>";
echo " <td>" . $row[0] . "</td>";
echo " <td>" . $row[1] . "</td>";
echo " <td>" . $row[2] . "</td>";
echo "</tr>";
}
echo "</table>";
在最坏的情况下,这将在构建阵列时暂时加倍内存使用量。